B
Hope this helps :)
Can I have Brainliest please
The expression for the cost of the ABC Book Club is 2x + 40. The expression for the cost of the Easy Book Club is 3x + 35. To find when the total charge for both book clubs is equal, the two expressions must equal each other. (x = the number of books read)
2x + 40 = 3x + 35
Subtract 35 from both sides.
2x + 5 = 3x
Subtract 2x from both sides.
5 = x
So, the total charge for each club is equal when 5 books are read.
Answer:
11
Step-by-step explanation:
Evaluate using
PEMDAS
First we do what is inside of the Parenthesis 12 - 9 = 3
Now we have 2 + 3²
Next is Exponents 3² = 9
Now we have 2 + 9
there is no multiplication or division needed so we go straight to addition
9 + 2 = 11
So we can conclude that the answer is 11
<u>Answer:</u>
a) 3.675 m
b) 3.67m
<u>Explanation:</u>
We are given acceleration due to gravity on earth =
And on planet given =
A) <u>Since the maximum</u><u> jump height</u><u> is given by the formula </u>

Where H = max jump height,
v0 = velocity of jump,
Ø = angle of jump and
g = acceleration due to gravity
Considering velocity and angle in both cases

Where H1 = jump height on given planet,
H2 = jump height on earth = 0.75m (given)
g1 = 2.0
and
g2 = 9.8
Substituting these values we get H1 = 3.675m which is the required answer
B)<u> Formula to </u><u>find height</u><u> of ball thrown is given by </u>

which is due to projectile motion of ball
Now h = max height,
v0 = initial velocity = 0,
t = time of motion,
a = acceleration = g = acceleration due to gravity
Considering t = same on both places we can write

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations
substituting h2 = 18m, g1 = 2.0
and g2 = 9.8
We get h1 = 3.67m which is the required height