3 years ago

What are the solutions of 2x^2+8x=-26? -2+\3i -2+\i 2+\6i -3+\2i

1 answer:

3 0

2x^2+8x+26=0

According to the . quadratic formula...

(-8+- $\sqrt{64-4(2)(26)}$ )/2=4

64-(4)(2)(26)=-144

$\sqrt{-144}$ = 12i

-8+-12i/4= -2+-3o

Answer A is correct

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2 years ago

Solve for x. 2 ( x + 1 ) = 12

Evgen [1.6K]

2 ( x + 1 ) = 12

Use distributive property:

2x + 2 = 12

Subtract 2 from both sides:

2x = 10

Divide both sides by 2:

X = 5

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