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Phoenix [80]
3 years ago
8

Use fraction bars and the rules of dividing signed numbers to divide. The quotient is

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

hello! your answer is 4. I just completed the assignment and got it correct. Hope it helps.

nexus9112 [7]3 years ago
5 0

Answer:

it's 4

Step-by-step explanation:

idk why someone deleted my answer-

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Find the tenth term in the following geometric sequence. 8, 4, 2, 1, . . .
Marrrta [24]

Answer:

  c)  0.0156

Step-by-step explanation:

The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...

  a[n] = a[1]r^(n-1)

The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...

  a[n] = 8(1/2)^(n-1)

The 10th term is then ...

  a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512

  a[10] = 0.015625 ≈ 0.0156

7 0
3 years ago
Lindo used 1/4 of the yard of fabric she bought for a sewing project how much fabric did she have left
maksim [4K]

Answer:

she has 3/4 of the material left or 75%

7 0
2 years ago
Which of the following is the area of the special trapezoid if AB = 10, CD = 10, and the height is 8.
Lelu [443]
Area of a trapezoid is A=height over 2 B1 +B2, so 10+10=20, then 20(8)=160, 160/2=80. Answer is b.
3 0
3 years ago
Read 2 more answers
Place the circles in order from the circle with the largest area to the circle with the smallest area.
11111nata11111 [884]

Answer:

Diameter 16, radius 7, circumference 37.68, diameter 8

Step-by-step explanation:

Largest area will be in a circle with the largest radius. So let's find all radii.

d = 8, so r = 4;

r = 7;

circumference = 2pi*r = 37. 68, so r = 6

diameter 18, so r = 8

5 0
3 years ago
Given any triangle in the plane, associate to each side an outward pointing normal vector of the same length as the side. Show t
Zigmanuir [339]

Let , a, b and c be the length of three sides of triangle, represented in terms of vectors as \vec{a},\vec{b},\vec{c}.

Now, vector of same Magnitude acts as normal vector to each side.

So, equation of any vector p having normal q is given by

      \vec{p} \times\vec{q}

Now sum of three vector and it's normal is given as

    =\vec{a} \times\vec{a}+\vec{b} \times\vec{b}+\vec{c} \times\vec{c}\\\\=0+0+0\\\\=0

Cross product of two identical vectors is Zero.

\rightarrow \vec{i} \times\vec{i}=0

8 0
3 years ago
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