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IrinaK [193]
3 years ago
7

Solve -20 - 5 > 3. Which graph shows the solutions?

Mathematics
1 answer:
Trava [24]3 years ago
7 0

Answer:

Third option is correct

Step-by-step explanation:

Given: -2a-5>3

To choose: the correct option

Solution:

-2a-5>3

-2a>3+5\\-2a>8

Multiply both sides by - 1

2a

For a, it includes all numbers less than -4

The graph is as follows:

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Evgesh-ka [11]
There seems to be a flaw with this question because it says that there are five x-intercepts but the given information only gives you 4 x-intercepts to work with.

Even means the graph is symmetric about the y-axis

The best answer is <span>A.(–6, 0), (–2, 0), and (0, 0)

because you do not have to worry about another point (0,0). Plus we need (-6,0) for it to be symmetric with (6,0).

Consider function f(x) = x²(x-6)(x+6)(x+2)</span>²(x-2)<span>². It is even and fits these conditions as it has x-intercepts at (6,0), (-6,0), (-2,0), (2,0), and (0,0). again, the question does not tell us the fifth x-intercept, so we need to assume that there is another one that needs to be there...and so (-2,0) must have (2,0) for it to be even as well.</span>
4 0
2 years ago
Read 2 more answers
What is the distance around a triangle that has measuring 2 1/8 feet,3 1/2 feet, 2 1/2 feet
N76 [4]

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Hope this will help you!

3 0
3 years ago
Opposite reciprocal of -2/3? geometry/algebra
Ulleksa [173]
The answer would be -3/2

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8 0
3 years ago
The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the fi
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Answer:

second term: 9

4th term:81

(3rd \: term)^{2}  = 9 \times 81

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\sqrt{729}  = 27

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{9}^{2}  = a1x27 \\ 81 = 27a1

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81 = 3 \times {q}^{3}

{q}^{3}  = 27

q=3

s = 3x \frac{1 -  {3}^{5} }{1 - 3}  = 364.5

5 0
3 years ago
How is multiplying exponents (x^2*x^4) different from raising a power to a power((x^2)^4)? Ty =)
Contact [7]

Answer:

When your multiplying exponents in the same parenthasis like x^2*x^4, you'll add the exponents so it will be x^6. If it is outside the parenthasis like (x^2)^4 you'll multiply the exponents so it will be x^8. good luck! :)

Step-by-step explanation:

8 0
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