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Nataly_w [17]
3 years ago
13

Find the smallest square number divisible by each of these numbers 6,9,and 15

Mathematics
2 answers:
Zigmanuir [339]3 years ago
8 0
  • <em>Answer:</em>

<em>900</em>

  • <em>Step-by-step explanation:</em>

<em>6 = 2×3</em>

<em>9 = 3²</em>

<em>15 = 3×5</em>

<em>lcm = 2×3²×5 = 90</em>

<em>to have a square number multiple of 90 we have to multiply by 2 and 5</em>

<em>2×3²×5 × 2×5 = 2²×3²×5² = (2×3×5)² = 30² = 900</em>

<em>Good luck !</em>

<em />

<em> </em>

<em />

<em />

STALIN [3.7K]3 years ago
6 0

Answer:

\frac{6}{3}  = 2

\frac{9}{3}  = 3

\frac{15}{3}  = 5

So the smallest number is 3. As it divides 6,9 and 15.

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Step-by-step explanation:

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where r = 4 km radius

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<u>plugin values into the formula</u>

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2 years ago
What is the rule for this pattern? 1st term:32, 2nd term:36, 3rd<br>term:40​
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Answer:

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Step-by-step explanation:

32, 36, 40

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Hope this helped!

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2 years ago
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A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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If i have a lawn mower for 3 $ and its 50 percent of what is the orginial price ?
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Answer:

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Step-by-step explanation:

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