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s344n2d4d5 [400]
2 years ago
9

45.83333333 as a fraction

Mathematics
2 answers:
PolarNik [594]2 years ago
5 0

Answer:

4583 / 100

Step-by-step explanation:

hammer [34]2 years ago
3 0

Answer:

275/6

Step-by-step explanation:

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If y=27 when x= 8 find y when x =11
Rina8888 [55]

Answer:

37 1/8

Step-by-step explanation:

The problem probably assumes direct variation

y=kx

IF so, then plug in the values and solve for k

27=k(8)

k = 27/8

y= (27/8)x.  Now let x = 11

y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8

y = 37 1/8

the problem is making some assumption about the relation between x and y.  The simplest assumption that's likely is direct variation,  that x and y are linearly related.  The graph is a straight line through the origin with slope = 27/8

6 0
2 years ago
In x^a=y, y^b=z, z^c=x, then prove that abc=1​
Marysya12 [62]

Step-by-step explanation:

Let, x^a =y......(1) and

y^b =z.....(2) and

z ^c =x......(3).

Now, using (1) in (2) we get,

x ^ab =z......(4).

Now, using (4) in (3) we get,

x ^abc =x

or, x ^abc =x ^1

or, abc=1.

Hope it will help :)

7 0
2 years ago
Read 2 more answers
Does anyone know how to solve this?
daser333 [38]

Answer:

The right answer is C ( π/2)

6 0
3 years ago
Calculate −5^2+(−2)^3
svetlana [45]

Answer:

-33

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the slope, as a decimal number, of the line that passes through the points (-1,7) and (-3,6)
Novay_Z [31]

Answer:

the slope is 1/2 or 0.5

Step-by-step explanation:

to know how to find the slope of an equation using given points

There are three steps in calculating the slope of a straight line when you are not given its equation.

  • Step One: Identify two points on the line.

(-1,7) and (-3,6)

Step Two: Select one to be (x1, y1) and the other to be (x2, y2).

(x1, y1)= -1, 7 and (x2, y2)= -3,6

Step Three: Use the slope equation to calculate slope.

equation: m= y2-y1/x2-x1

                      =6-7/-3-(-1)

                      =-1/-2

                      =1/2 or 0.5

6 0
3 years ago
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