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soldi70 [24.7K]
3 years ago
8

An object of 6 cm height is 16 cm in front of a converging lens with focal length of magnitude 4 cm. What is the dimension of th

e image(include the unit and if it is the case the sign)?
Physics
1 answer:
Pani-rosa [81]3 years ago
3 0

Answer:

- 2 cm

Explanation:

h_{o} = height of the object = 6 cm

d_{o} = distance of the object from the lens = 16 cm

f = focal length of the lens = 4 cm

d_{i} = image distance

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{16} + \frac{1}{d_{i}} = \frac{1}{4}

d_{i} = \frac{16}{3} cm

h_{i} = height of the image

Using the equation

\frac{h_{i}}{h_{o}} = \frac{- d_{i}}{d_{o}}

\frac{h_{i}}{6} = \frac{- \frac{16}{3}}{16}

h_{i} =-2 cm

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