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vazorg [7]
3 years ago
8

Let a,b,c ∈ Z. Define the highest common factor hcf(a,b,c) to be the largest positive integer that divides a,b and c. Prove that

there are integers s,t,u such that hcf(a,b,c) = sa+tb+uc. Find such integers s,t,u when a = 91, b = 903, c = 1792
Mathematics
1 answer:
kakasveta [241]3 years ago
8 0

21 they have too be right next to each other and threy have too be right

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WILL MARK BRAINLEIST PLZ HELP
Dmitry [639]

Answer:

28

Step-by-step explanation:

The scale factor is 3.5 which is found out by doing 14 divided by 4. Once you know the scale factor you simply have to do 8 multiplied 3.5 which equals 28.

8 0
3 years ago
What is the volume?<br> 2 mm<br> 8 mm<br> 4 mm<br> cubic millimeters
shutvik [7]

Answer:

64 mm³

Step-by-step explanation:

I am assuming there was a photo to go with this problem

However the general formula to find volume is usually V = l×w×h

  • It does not matter which measurement is which because they all get multiplied together.
  • However assigning a name to each unit of measurement we will denoted the length (l) as 2 mm, the width (w) as 8 mm, and the height (h) as 4 mm
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6 0
3 years ago
Asking again! Please solve! For both! Brainliest and lots of points!
Dennis_Churaev [7]

Answer:

1 D (10, 120)

2 C (20, 40)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which values of x are solutions of the equation below
Mandarinka [93]

Answer:

x = 3.3 and -0.3

Step-by-step explanation:

Given the expression

1/x-4 + x/x-2=2/x^2-6x+8

Find the LCM

x-2+x(x-4)/(x-4)(x-2) = 2/x^2-6x+8

Since the denominator, are the same they cancels out

x +1 + x(x-4) = 2

x+1 + x²-4x = 2

x²-3x + 1 - 2 = 0

x² - 3x - 1 = 0

Factorize

x =3±√9+4/2

x =3±√13/2

x = 3±3.6/2

x= 6.6/2 and -0.6/2

x = 3.3 and -0.3

4 0
3 years ago
Simplify as much as possible:<br> (7nm5o2) (-3m3o5)2
Yakvenalex [24]

Answer:

63m^11 no^12

Step-by-step explanation:

Dont know if thats o or and zero but I solve it by using o..if it was a zero then comment that so I can redo it anyways heres the explanation

(7nm^5 o^2) × (-3m^3 o^5)^2

7m^5 no^2) ×(-3m^3 o^5) ^2

(7m^5 no^2) × (3m^3 o^5)^2

7m^5 no^2 × (3m^3 o^5) ^2

7m^5 no^2 × 9m^6 o^10

63m^11 no^12

3 0
3 years ago
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