Ok so basically you have to look at the work and then look at the work and then it will show
Torque acting dowward = 6 x 0.5 = 3 Nm
Torque acting to the right = 5 x 1 = 5 Nm
5 - 3 = 2 Nm
inertia = 1/2 mr^2
0.5 x 10 x 1^2 = 5 kg-m^2
2/5 = alpha = 0.4 rad /s^2
Hope this helps
Answer:
a= 2 m/s^2
Explanation:
take to the right as positive
let Ftot be the total forces acting on the box , m be the mass of the box and a be the acceleration of the box.
Ftot = 10 - 2 = 8 N
and,
Ftot = ma
a = Ftot/m
= 8/4
= 2 m/s^2
therefore, the acceleration of the box is of magnitude of 2 m/s^2.
Correct Answer: Option C
<em>Explanation
</em>
X = ut + 12at2
= (0 x 4) + (12 x 0.1 x 4 x 4)
= 0.8m
workdone = force x distance
= 40 x 0.8
= 32J
Answer:
Speed, S = 0.5m/s
Explanation:
Given the following data;
Distance = 30 meters
Time = 1 minute = 60 seconds
To find the speed;
Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.
Mathematically, speed is given by the equation;
Substituting into the above formula;
Speed, S = 0.5m/s