Answer:
At the center of the object
At the end of the object farthest away from the ground
At the center of gravity of the object
At end of the object closest to the ground
Explanation:
Answer:
42.5W
Explanation:
To solve this problem we must go back to the calculations of a weighted average based on the time elapsed thus,

We need to calculate the average power dissipated by the 800\Omega resistor.
Our values are given by:


Aplying the values to the equation we have:



An electrically charged element is called an "ion". A neutral element is an atom.
<span>Formula-
E = hc/ {wavelength}
Given in quation-wavelength=12.4 cm
We know the value of h and c.
h=6.626 * 10^-34 Js
c= 2.997 * 10^8 m/s
wavelength=12.4 cm converted to 0.124 m
E = [ 6.626 * 10^-34 Js * 2.997 * 10^8 m/s ] / 0.124 m
E = 1.60 * 10^-24 J
1.60 * 10^-24 J of energy of exactly one photon of this microwave radiation have.</span>
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