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Andru [333]
3 years ago
7

Moving at 3.2m/s slows down after 32 seconds moving at 1.2m/s What is his acceleration?

Physics
1 answer:
Stels [109]3 years ago
8 0

Answer:

His acceleration is -0.0625 m/s².

Explanation:

Given:

Initial velocity is, u=3.2\ m/s

Final velocity is, v=1.2\ m/s

Time taken for the change is, t=32\ s

Acceleration of a body is defined as the rate at which the velocity is changing. Acceleration is positive if there is increase in velocity with time and acceleration is negative when the body slows down or there is decrease in velocity with time.

Here, there is decrease in velocity over the given time. Therefore, the acceleration is negative and is given as:

a=\frac{v-u}{t}\\\\a=\frac{1.2-3.2}{32}\\\\a=\frac{-2}{32}=-0.0625\ m/s^2

Therefore, his acceleration is -0.0625 m/s².

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Given:

A cylindrical container closed of both end has a radius of 7cm and height of 6cm.

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