Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,

Substitute in the formula to get the side,

![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)

We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
Answer:
RD = 162 cm
Step-by-step explanation:
LD = 2 RL = 2* 54 = 108
RD = RL + LD
RD = 54 + 108
RD = 162 cm
area 4 ft
-__________________________________________________________-
The formula for volume of a cone is V=(1/3)*h*π*(r^2)
our height is 7.5 feet, and since the length of the base of the cone (diameter) is 22 feet long, the radius is 11 feet long.
(1/3)*7.5*π*(11^2)=302.5*π=950.3
so the volume of the house is about 950 feet cubed.