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Y_Kistochka [10]
3 years ago
12

Solve the equation for y. 8x – 9y = 11

Mathematics
2 answers:
borishaifa [10]3 years ago
6 0

Watch carefully:

                                             <u>8x - 9y = 11</u>

Add  9y  to each side:                    8x = 11 + 9y

Subtract  11  from each side:    8x - 11 = 9y

Divide each side by  9 :        <em>y = 1/9 of (8x - 11) </em>


Aleksandr-060686 [28]3 years ago
3 0
8x-9y=11 subtract 8x from both sides -9y= -8x+11 divide both sides by -9 y= 8/9x-11/9 hope this helps
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Step-by-step explanation:

reflection

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3 years ago
Please help! geometry problem 3!
Vilka [71]
Comment
|First of all, the triangles are equal by ASA the way the diagram has been marked.

B and E are both right angles.
Side BC = Side DE
<BCA =< EDA 

So triangle BCA = triangle EDA

Now to the letters.
x = y - 1                 Add 1 to both sides.
x + 1 = y                (1)
3x - 2 = 2y + 1       Subtract 1 from both sides.
3x -2 - 1 = 2y
3x - 3 = 2y             Divide by 2
3x/2 - 3/2 = 2y/2
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Step One
Since (1) and (2) both have y isolated on their respective right sides, they can be equated.

1.5x - 1.5 = x + 1       Take an x from both sides.
0.5x - 1.5 = x - x + 1
0.5x - 1.5 = 1           Add  1.5 to both sides.
0.5x =  1 + 1.5
0.5x = 2.5                 Divide 0.5 on both sides.
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x = 5

Now we need a y value.
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So the 2 sides and the 2 angles are equal when 
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C Answer <<<<<<



 


4 0
3 years ago
<img src="https://tex.z-dn.net/?f=3%2F5%20of%205%2F9%5C%5C" id="TexFormula1" title="3/5 of 5/9\\" alt="3/5 of 5/9\\" align="absm
pychu [463]

Answer:

<u>⅓</u>

<h2>Step-by-step explanation:</h2>

\frac{5}{9}  \times  \frac{3}{5}

=  \frac{1}{3}  \times  \frac{1}{1}

=  \frac{1}{3}

<h2>Checking:</h2>

\frac{1}{3}  \div  \frac{3}{5}

=  \frac{1}{3}  \times  \frac{5}{3}

=  \frac{5}{9}

#CarryOnLearning

8 0
3 years ago
Read 2 more answers
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PLEASE HELP ME!! THANK YOU!!
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Answer:

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Step-by-step explanation:

The domain is the left-right (horizontal) extent of the function. The dots at the end of the continuous line are solid, so the brackets on the interval are square brackets.

The left dot is at x=-4; the right dot is at x=3, so the domain is ...

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