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Ronch [10]
2 years ago
7

An engine has an imput of 100 j and gives out 27 j of useful kenetic energy what is the efficiency of the engine

Physics
1 answer:
Lunna [17]2 years ago
4 0

Answer:

Based on what we have learned so far, in what ways have the experiences of Asian-Canadians stayed the same over time? Why do you think these similarities exist? Please give specific examples to support your ideas.

Explanation:

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which of the following laboratory tool would be most appropiate for measuring the approximate volume of a liquid?
SIZIF [17.4K]
Beaker would be most appropriate for measuring the approximate volume of a liquid.
7 0
3 years ago
Two radio antennas A and B radiate in phase. Antenna B is a distance of 120 m to the right of antenna A. Consider point Q along
LuckyWell [14K]

Answer:

240 m

120 m

Explanation:

d = Path difference = 120 m

For destructive interference

Path difference

d=\dfrac{\lambda}{2}\\\Rightarrow \lambda=2d\\\Rightarrow \lambda=2\times 120\\\Rightarrow \lambda=240\ m

The longest wavelength is 240 m

For constructive interference

d=\lambda\\\Rightarrow 120\ m=\lambda

The longest wavelength is 120 m

4 0
3 years ago
A 0.0750kg teddy bear is dropped from a deck that is 3.00m above the ground. What will be the velocity of the teddy bear as it s
FrozenT [24]

The velocity of the teddy bear as it strikes the ground is 7.67 m/s.

<h3>Velocity of the teddy when it strikes the ground</h3>

The velocity of the teddy when it strikes the ground is calculated from principle of conservation of energy as shown below.

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is height of fall of the teddy
  • g is acceleration due to gravity

v = √(2 x 9.8 x 3)

v = 7.67 m/s

Thus, the velocity of the teddy bear as it strikes the ground is 7.67 m/s.

Learn more about conservation of energy here: brainly.com/question/166559

#SPJ1

4 0
1 year ago
An iron ball and an aluminum ball of mass 100 g each are heated to the same temperature and then cooled to a temperature of 20°C
sertanlavr [38]

Answer:

b

Explanation:

i just answered it and the correct answer is b

5 0
3 years ago
The noise from a power mower was measured at 106 dB. The noise level at a rock concert was measured at 115 dB. Find the ratio of
andrey2020 [161]

Answer:

= 8

Explanation:

noise from power mower = 106 dB

noise from rock concert = 115 dB

we would be applying the formula for the decibel level of sound to get the intensities.

(B) = 10 log \frac{I}{I₀}

I = intensity of sound

I₀= reference intensity = 10^{-12} W/m^{2}

  • intensity of the power mower

106 = 10 log \frac{I}{10^{-12}}

10.6 =  log \frac{I}{10^{-12}}

10^{10.6} = \frac{I}{10^{-12}}

I = 10^{10.6} x 10^{-12}

I of power mower = 0.0398 W/m^{2}

  • intensity of the rock music

115 = 10 log \frac{I}{10^{-12}}

11.5 =  log \frac{I}{10^{-12}}

10^{11.5} = \frac{I}{10^{-12}}

I = 10^{11.5}  x 10^{-12}

I of rock music = 0.316 W/m^{2}

now the ratio of the intensity of the rock music to the power mower

= \frac{0.316}{0.0398}

= 8

4 0
3 years ago
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