We have to calculate the impulse of a hockey puck.
Imp = m * ( v 1 - v 2 ) = m * Δ v
v 1 = - 10 i m/s,
v 2 = ( 20 * cos 40° ) i + ( 20 * sin 40° ) j =
= ( 20 * 0.766 ) i + ( 20 * 0.64278 ) j = ( 15.32 i + 12.855 j ) m/s
Δ v = ( 15.32 i + 12.855 j ) - ( - 10 i ) =
= 15.32 i + 12.855 j + 10 i = 25.32 i + 12.855 j
| Δv | = √ ( 25.32² + 12.855²) = √806.35 = 28.4 m/s
Imp = 0.2 kg * 28.4 m/s = 5.68 N-s
Answer: D ) 5.68 N-s.
Answer:
a ,b , d ,e
Explanation:
took the k12 quiz and got a 100
Answer:
a=F/m
a=12N/3kg (here newton can be written as kgm/s^2 so kg will be cancelled)
a=4m/s^2
Explanation:
Answer:
due to the magnetic field
Explanation:
magnetic field is the same in the vacuum
Answer:
Explanation:
When the craft was stationary , weight will be balanced by tension
T = mg
T = 7000 N
A)
when the craft was being lowered to the seafloor
drag force will act in upper direction , so
T₁ + 1800 = mg
T₁ = mg - 1800
= 7000 - 1800
= 5200 N
52 X 10² N
B)
when the craft was being raised from the seafloor , Tension will act in downward direction
T₂ = mg+ 1800
T₂ = 7000 - 1800
= 8800N
