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3 years ago

What is the relationship that exist between the mole molar mass and avogadro number?

1 answer:

7 0

Avogadros number is the definition of a mole. SO a mole is 1 avogadros number of atoms. molar mass is how much 1 avogadros number of atoms weighs. each element on the periodic table has a different mass, so 1 mole of each of the elements has a different molar mass.

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A 200 g air-track glider is attached to a spring. The glider is pushed in 9.8 cm against the spring, then released. A student wi

Likurg_2 [28]

Answer:

k = 5.05 N/m

Explanation:

In order to calculate the spring mass of the system, you use the following formula:

$T=2\pi \sqrt{\frac{m}{k}}$ (1)

T: period of oscillation of the system

m: mass of the air-track glider = 200g = 0.200 kg

k: spring constant = ?

You first calculate the period of oscillation:

$T=\frac{1}{f}=\frac{1}{12/15.0s}=1.25s$

Next, you solve the equation (1) for k, and then you replace the values of the other parmateres:

$k=4\pi^2 \frac{m}{T^2}\\\\k=4\pi^2 \frac{0.200kg}{(1.25s)^2}=5.05\frac{N}{m}$

The spring constant of the spring is 5.05 N/m

6 0

2 years ago

A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5

sweet [91]

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

$y = \dfrac{m\lambda\ D}{d}$

for the first maxima, m = 1

$d = \dfrac{1\times \lambda\ D}{y}$

$d = \dfrac{1\times 550 \times 10^{-9}\times 1.5}{0.016}$

d = 5.2 x 10⁻⁶ m

d = 52 μm

hence, the width of her slits is equal to d = 52 μm

3 0

3 years ago

A ball falls off of a 3m tall shelf. How long will it take for the

natali 33 [55]

Answer:

0.8s

Explanation:

Given parameters:

Height of shelf = 3m

Unknown:

Time it will take to hit the ground = ?

Solution:

To solve this problem, we use the expression below;

x = ut + $\frac{1}{2}$ gt²

x is the height

u is the initial velocity = 0m/s

g is the acceleration due to gravity = 9.8m/s²

t is the time taken = ?

Now insert the parameters and solve for t;

3 = (0 x t) +( $\frac{1}{2}$ x 9.8 x t²)

3 = 4.9t²

t² = 0.6

t = 0.8s

7 0

3 years ago

(50 POINTS) please answer each question:

Advocard [28]

Answer:

i know the first one.

Explanation:

the distance from earth in light years is 6 trillion miles.

6 0

2 years ago

Your 64-cm-diameter car tire is rotating at 3.3 rev/swhen suddenly you press down hard on the accelerator. After traveling 250 m

umka21 [38]

Answer:

0.76 rad/s^2

Explanation:

First, we convert the original and final velocity from rev/s to rad/s:

$v_o = 3.3\frac{rev}{s} * \frac{2\pi rad}{1rev} =20.73 rad/s$

$v_f = 6.4\frac{rev}{s} * \frac{2\pi rad}{1rev}=40.21 rad/s$

Now, we need to find the number of rads that the tire rotates in the 250m path. We use the arc length formula:

$D = x*r \\x = \frac{D}{r} = \frac{250m}{0.64m/2} = 781.25 rads$

Now, we just use the formula:

$w_f^2-w_o^2=2\alpha*x$

$\alpha =\frac{w_f^2-w_o^2}{2x} = \frac{(40.21rad/s)^2-(20.73rad/s)^2}{2*781.25rad} = 0.76 rad/s^2$

6 0

2 years ago

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