Answer:
<u>Acceleration is 2 m/s² </u>
<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>
Explanation:
From definition of acceleration, Acceleration is the rate of change in velocity.
• Simplifying the definition, or modifying it;
• Let's formulate symbols:
- a is acceleration
- v is final velocity, v = 20 m/s
- u is initial velocity, u = 0 m/s [ at rest ]
- t is time, t = 10 seconds
Distance = ut + ½at²
Distance = (0 × 10) + (½ × 2 × 10²)
Distance = 0 + 10²
Distance = 100 meters
First convert 90km/hr to m/s.
Initiate velocity = 0m/s (car was at rest)
Final velocity is 25m/s (90km/hr converted)
25m/s - 0m/s / 8s = 3.125 m/s^s
Therefore the answer is option A (3.13m/s^2)
Answer:
Positively charged objects have electrons; they simply possess more protons than electrons.
Explanation:
2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.
<h3>Information:</h3>
If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.
<h3>Tips:</h3>
If it loses an electron, it becomes positively charged and is known as a cation.
<h2>I hope this answers help you! :></h2>
Answer:
d. causes the cell to make more viruses
Explanation:
Viruses depend on the host cells that they infect to reproduce. When found outside of host cells, viruses exist as a protein coat or capsid, sometimes enclosed within a membrane. The capsid encloses either DNA or RNA which codes for the virus elements.
The frequency of the human ear canal is 2.92 kHz.
Explanation:
As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is
Wavelength=4*Length of the ear canal
As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:
Then the frequency is determined as
f=c/λ=339/0.116=2922 Hz=2.92 kHz.
So, the frequency of the human ear canal is 2.92 kHz.
