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Korolek [52]
3 years ago
10

What is the relationship that exist between the mole molar mass and avogadro number?

Physics
1 answer:
Elenna [48]3 years ago
7 0
Avogadros number is the definition of a mole. SO a mole is 1 avogadros number of atoms. molar mass is how much 1 avogadros number of atoms weighs. each element on the periodic table has a different mass, so 1 mole of each of the elements has a different molar mass.
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Someone help me answer this question. What are the nuclear reactions in the human body ?
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Answer:

are chemical processes and not nuclear processes. Nuclear reactions do indeed occur in the human body, but the body does not use them. Nuclear reactions can lead to chemical damage, which the body may notice and try to fix.

4 0
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Are the phases of the moon the same everywhere on earth
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Yes. Everybody on Earth sees the same moon phase at the same time.
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3 years ago
Name a suitable plece of equipment that could be used to measure the length of the pool.​
Fynjy0 [20]

Answer:

With a tape measure.

Explanation:

We can use a big tape measure, this tape is in the market and we can use the one with the proper length that lets us measure different sections of the total length of the pool.

4 0
4 years ago
A toy cork gun contains a spring whose spring constant is 10.0N/m. The spring is compressed 5.00cm and then used to propel a 6.0
valentina_108 [34]

Answer:

The muzzle velocity of this cork is 2 m/s.                                

Explanation:

It is given that,

Spring constant of the spring, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

According to the law of conservation of energy, the initial potential energy of the spring is equal to the sum of final spring potential energy and the kinetic energy of cork such that,

\dfrac{1}{2}kx^2=\dfrac{1}{2}kx'^2+\dfrac{1}{2}mv^2

v is the muzzle velocity of this cork.

kx^2=kx'^2+mv^2      

v=\sqrt{\dfrac{k(x^2-x'^2)}{m}}

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4 0
4 years ago
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Artemon [7]

Answer:

0.14 J

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ω = √(k / m)

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The elastic potential energy is:

EE = ½ kx²

EE = ½ (142 N/m) (0.044 m)²

EE = 0.14 J

6 0
3 years ago
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