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3 years ago

What type of bond is formed when two nonmetal atoms get close enough for their orbitals to overlap?

2 answers:

7 0

Metal with metal = metallic Metal with non mental = ionic Non metal with non metal = covalent So the answer is covalent :)

Gala2k [10]3 years ago

3 0

The type of bond that forms when two nonmetal atoms get close enough for their orbitals to overlap is called a covalent bond. Because both of these atoms are nonmetallic, neither atom has enough electronegativity to give up an electron to each other. What the atoms do, is the overlap their orbitals. The electrons in the shared orbitals can be considered to be in a covalent bond. They are held together by the attraction of both nuclei to the shared electrons.

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Why was it important to establish the Clean Air Act?

frosja888 [35]

Answer:

It was important to establish the clean air act to create a regulation that makes any activities pollute the air illegal

Explanation:

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3 years ago

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Determine the ph of 0.57 m methylamine (ch3nh2) with kb = 4.4 x 10-4 : ch3nh2(aq)+ h2o(l) ⇌ ch3nh3+ (aq) + oh- (aq)

k0ka [10]

Answer is: pH of methylamine is 12,2.
Chemical reaction: CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻(aq).
Kb(CH₃NH₂) = 4,4·10⁻⁴.

c₀(CH₃NH₂) = 0,57 M.

c(CH₃NH₃⁺) = c(OH⁻) = x.

c(NH₂OH) = 0,57 M - x.

Kb = c(CH₃NH₃⁺) · c(OH⁻) / c(CH₃NH₂).

0,00044 = x² / (0,57 M - x).

Solve quadratic equation: x = c(OH⁻) = 0,0156 mol/L.

pOH = -log(0,0156 mol/L.) = 1,80.

pH = 14 - 1,80 = 12,2.

4 0

4 years ago

Read 2 more answers

Given that a mass of a ball is (36.0 g), and the volume is (8.0 mL), what is the ball's density in g/mL?

max2010maxim [7]

Answer:

4.5g/mL

Explanation:

Given parameters:

Mass of ball = 36g

Volume of the ball = 8mL

Unknown:

Density of the ball = ?

Solution:

Density is the mass per unit volume of a substance.

Density = $\frac{mass}{volume}$

So;

Density = $\frac{36}{8}$ = 4.5g/mL

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3 years ago

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Tems11 [23]

Answer:

True

Explanation:

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3 years ago

PLEASE HELP!!!!!!

jeyben [28]

Answer: The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

Explanation:

We are given:

Average number of drops of sodium bicarbonate = 142

The chemical equation for the reaction of sodium bicarbonate and acetic acid in vinegar follows:

$NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2CO_3$

From the stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.

Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

4 0

3 years ago