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3 years ago

Can you identify how an animals adoption allows it to survive in its habit

1 answer:

dsp733 years ago

4 0

Animals adapt to their needs and the things they need to do or to have in order to survive. The Galapagos Finch has different beak sizes in order to eat larger nuts or seeds.

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How much heat energy is required to raise the temperature of 0.360 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of co

AVprozaik [17]

MThe heat energy required to raise the temperature of 0.36Kg of copper from 22 c to 60 c is calculate using the following formula

MC delta T
m(mass)= 0.360kg in grams = 0.360 x1000 = 360 g
c(specific heat energy) = 0.0920 cal/g.c
delta T = 60- 23 = 37 c

heat energy is therefore= 360g x0.0920 cal/g.c x 37 c= 1225.44 cal

5 0

3 years ago

Which structure is most likely found in all fish.

stellarik [79]

gills are most likely found in all fish

3 0

4 years ago

Which term describes the part of the periodic table that is arranged by increasing atomic number and repeats periodically?

erastovalidia [21]

Answer:

period

Explanation:

8 0

3 years ago

What shows the shape and appearance of the arrangement of atoms in a compound?

Lunna [17]

The shape and arrangement in atoms in a compound are lattice patterns as they have high melting and boiling points

4 0

3 years ago

Octane has a density of 0.692 g/ml at 20oc. how many grams of o2 are required to burn 15.0 gal of c8h18 (the average capacity of

Hatshy [7]

Octane has a density of 0.692 g/ml at 20°C. Grams of O₂ required to burn 15.0 gal of C₈H₁₈ is 1.37868×10⁵g.

Octane is a hydrocarbon having eight carbon atoms and have single bonds only.

Given,

Density of octane = 0.692g/ml

Temperature = 20°C = 293K

Amount of Octane present = 15gal

Molar mass of octane = 114g

We know that,

1 gal = 3.78541L = 3785.4ml

Hence, 15 gal = 56781 ml

Now let's calculate the Mass of octane required:

Mass of octane = 0.692 x 56781

Mass of octane = 39292.45 g

According to the given equation,

C₈H₁₈ + 12.5O₂ ---------> 8CO₂ + 9H₂O

Also, 114g of octane needs-------> 400g of oxygen

39292.45g of octane needs ---------> 137868.24g of oxygen

Hence, oxygen needed to burn octane is 1.37868×10⁵g

Learn more about Octane here, brainly.com/question/21268869

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4 0

2 years ago