Molar mass of A1C1 3

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

Kipish [7]

pV = nRT

p = nRT/V

p= 1 x 0.08205 x 1000/ 2

p = 41.025 Pa

Edit: The unit should be atm instead of Pa, as pointed out by a nice human being.

4 0

4 years ago

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How do the different spheres of earth interact?

Vikki [24]

South Pole and north Pole . it's about megnetic field different spheres of earth interact

5 0

3 years ago

A solid with a density of 3.57g/mL and mass of 19.5g is added to a graduated cylinder that contain 23.2mL of water. What is the

NNADVOKAT [17]

Answer:

Volume of liquid = 28.7 mL

Explanation:

Given data;

Density of solid = 3.57 g/ml

Mass of solid = 19.5 g

Volume of water = 23.2 mL

Total volume when solid is dropped into graduated cylinder= ?

Solution:

Density = mass/ volume

v = m/d

v = 19.5 g/ 3.57 g/ml

v = 5.5 mL

Volume of liquid = volume of water + volume of solid

Volume of liquid = 23.2 mL + 5.5 mL

Volume of liquid = 28.7 mL

3 0

3 years ago

A solute is a strong electrolyte that ionizes into 2 ions. What is the molar mass of this solute if 30.76 grams added to exactly

Whitepunk [10]

Answer:

34.9 g/mol is the molar mass for this solute

Explanation:

Formula for boiling point elevation: ΔT = Kb . m . i

ΔT = Temperatures 's difference between pure solvent and solution → 0.899°C

Kb = Ebullioscopic constant → 0.511°C/m

m = molality (moles of solute/1kg of solvent)

i = 2 → The solute is a strong electrolyte that ionizes into 2 ions

For example: AB ⇒ A⁺ + B⁻

Let's replace → 0.899°C = 0.511 °C/m . m . 2

0.899°C / 0.511 m/°C . 2 = m → 0.879 molal

This moles corresponds to 1 kg of solvent. Let's determine the molar mass

Molar mass (g/mol) → 30.76 g / 0.879 mol = 34.9 g/mol

4 0

3 years ago

You are given an unknown gaseous binary compound (that is, a compound consisting of two different elements). when 10.0 g of the

Luda [366]

Answer is: a possible identity for the unknown compound is C₃H₈.

m(binary compound) = 10.0 g.

m(H₂O) = 16.3 g; mass of water.

M(O₂) = 32 g/mol; molar mass of oxygen.

M(binary compound) = 1.38 · 32 g/mol.

M(binary compound) = 44.16 g/mol.

n(binary compound) = 10 g ÷ 44.16 g/mol.

n(binary compound) = 0.225 mol; amount of substance.

n(H₂O) = 16.3 g ÷ 18 g/mol.

n(H₂O) = 0.9 mol; amount of water.

m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.

m(H₂O) : n(binary compound) = 4 : 1.

Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.

Second element in compound is carbon:

M(X) = 44.16 g/mol - 8 · 1.01 g/mol.

M(X) = 36.08 g/mol ÷ 3.

M(C) = 12.01 g/mol.

8 0

3 years ago