There are four 7's in a standard card. Chance of getting a 7 first is 4/52 = 1/13
There are four queens in a standard card. Chance of getting a queen in the second drawing is 4/51 and chance of getting a queen in the third drawing is 3/50.
Therefore, chance of drawing a seven and two queens is 1/13 x 4/51 x 3/50 = 2/5525
Answer:
Step-by-step explanation:
<u>Given sets</u>
- R = {10, 15, 20}
- S = {20, 25}
<u>Intersection of sets</u>
171 19/32=(171×32+19)/32=(odd number)/32.
But 32=2⁵
Thus, this ratio cannot be simplified, because the numerator is an odd number.
And the denominator is a power of 2.
Answer:
stop cheating on your schoology test;)
Step-by-step explanation:
Given:
The given function is:
To find:
The value of x that is in the domain.
Solution:
Domain is the set of input values.
We have,
We know that the square root is defined for non negative values. So,
Thus, the domain of the given function is all real number that are greater than or equal to 7.
In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So, 
is in the domain of the given function.
Therefore, the correct option is A.
