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Lubov Fominskaja [6]
3 years ago
7

The amount of money Blain earns as a service technician after x hours is modeled by the equation y = $20x + 100. What is the mea

ning of the $20 in this model?
Mathematics
1 answer:
Margarita [4]3 years ago
3 0
The $20 in the model means that Blain works for $20 dollars per hour

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8c=5c+21 What would that be
NemiM [27]
To solve for C, you have to get both of the numbers with a C on the same side.  So, subtract the 5c from the right side onto the left side.

8c = 5c + 21\\8c - 5c = 5c - 5c + 21\\3c = 21

Then, divide by 3 on each side.

3c = 21\\3c /3 = 21/3\\c = 7

So, c = 7.
7 0
3 years ago
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kakasveta [241]
\begin{gathered} c)\text{ output = (input}\times\text{ input) }+\text{ 1} \\ d)\text{ output = input + 5} \end{gathered}

Explanation:

\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}

\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}\text{output = input + 5}

5 0
1 year ago
If [infinity] cn8n n = 0 is convergent, can we conclude that each of the following series is convergent? (a) [infinity] cn(−3)n
pashok25 [27]

Answer:

a) we know that this is convergent.

b) we know that this might not converge.

Step-by-step explanation:

Given the \sum^\infty_{n=0}C_n8^n is convergent

Therefore,

(a)  \sum^\infty_{n=0}C_n(-3)^n The power series \sum C_nx^n has radius of convergence at least as big as 8. So we definitely know it converges for all x satisfying -8<x≤8. In particular for x = -3

∴ \sum^\infty_{n=0}C_n(-3)^n  is convergent.

(b) \sum^\infty_{n=0}C_n(-8)^n -8 could be right on the edge of the interval of convergence, and so might not converge

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Answer:

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Answer:

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Step-by-step explanation

That would be  3 * 300 = 900

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