All categories

2 years ago

4/9 + 2/3 - 1/2 in simplest form

Mathematics

1 answer:

Oksana_A [137]2 years ago

4 0

$\frac{4}{9} + \frac{2}{3} - \frac{1}{2}$
$\frac{10}{9} - \frac{1}{2} =$
$\frac{11}{8}$

ANSWER
$\frac{11}{8}$

You might be interested in

Gambar grafik fungsi kuadrat dari y=x²-x-6

sveticcg [70]

-x^2-x+y-6 Should be right
y=x^2-x-6 = x^2-x+y-6

4 0

3 years ago

Which number is the best approximation for 52√+23√ ?

Agata [3.3K]

<span>52√+23√ = 4.79

Approx 5.1 is the answer.

Hope that helps. -UF aka Nadia
</span>

6 0

3 years ago

What is the side length of a cube with a volume of 0.216 m3?

aksik [14]

｡☆✼★ ━━━━━━━━━━━━━━━ ☾

Cube root 0.216 to get your answer

(Note: This makes sense if you know the volume of a cube is the same value multiplied together 3 times)

The answer is option A 0.6 m

Have A Nice Day ❤

Stay Brainly! ヅ

- Ally ✧

｡☆✼★ ━━━━━━━━━━━━━━━━ ☾

6 0

3 years ago

A box contains 8 two-inch screws. Four have a Phillips head and 4 have a slotted head. In how many ways can 4 screws be chosen s

hammer [34]

Answer:

There are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

Step-by-step explanation:

If 4 screws must be chosen so that 2 have a Phillips head and 2 have a slotted head, then you have to choose 2 screws with a Phillips head from 4 screws with a Phillips head and 2 screws with a slotted head from 4 screws with a slotted head.

You can choose 2 screws with a Phillips head from 4 screws with a Phillips head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

You can choose 2 screws with a slotted head from 4 screws with a slotted head in

$C^4_2=\dfrac{4!}{2!(4-2)!}=\dfrac{4!}{2!\cdot2!}=\dfrac{1\cdot2\cdot3\cdot4}{1\cdot2\cdot1\cdot2}=6$

different ways.

In total there are $6\cdot 6=36$ different ways to choose 4 screws such that 2 have a Phillips head and 2 have a slotted head.

7 0

2 years ago

Factor this polynomial using the GCF: 3xy^2 + 3xy^2 - 3xy

Olenka [21]

3xy^2 + 3yx^2 - 3xy....GCF is 3xy

3xy(y + x - 1) <==

7 0

3 years ago