Question

In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard error of the proportion for this group?

Answer 1

Step-by-step explanation:

The standard error for a proportion is √(pq/n), where q=1−p.

√(0.301 × 0.699 / 83) ≈ 0.050