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riadik2000 [5.3K]

3 years ago

10

In a survey sample of 83 respondents, about 30.1% of the sample work less than 40 hr per week. What is the estimated standard er

ror of the proportion for this group?

1 answer:

notka56 [123]3 years ago

5 0

Step-by-step explanation:

The standard error for a proportion is √(pq/n), where q=1−p.

√(0.301 × 0.699 / 83) ≈ 0.050

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From what I can tell you are supposed to just pick Radom numbers and calculate what his earnings would be for the time worked

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3 years ago

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Ksivusya [100]

Answer:

Step-by-step explanation:

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$19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\$

$20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}$

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2 years ago

plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi

erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar $= length \times width\times height$

Plugging the values in the equation we get,

Volume of the gold bar $=18.00 \times 9.21 \times 4.45= 737.721cm^3$

Now that we have the volume we can find the mass by using the formula,

$Mass= density \times volume$

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

$Mass = 19.32\times 737.721=14252.769$ grams

So, the mass of the gold bar is 14252.769 grams

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3 years ago

(9x + 5) - (4x + 3) =

mrs_skeptik [129]

Answer:

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Step-by-step explanation:

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3 years ago

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Evaluate g(n-7) if g(x) =x^2-5 / 3x

aleksandrvk [35]

Answer:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

Step-by-step explanation:

The given function is

$g(x)=\frac{x^2-5}{3x}$

To find g(n-7), we substitute x=n-7 to obtain;

$g(n-7)=\frac{(n-7)^2-5}{3(n-7)}$

Expand the parenthesis to obtain;

$g(n-7)=\frac{n^2-14n+49-5}{3n-21}$

Simplify:

$g(n-7)=\frac{n^2-14n+44}{3n-21}$

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3 years ago