How many total operations do you have when multiplying two 4X4 matrices?

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif

algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) $t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

e) $p_v =P(t_{118}$

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

$\bar X_{O}=2.91$ represent the mean for the Orange Coast

$\bar X_{C}=2.96$ represent the mean for the Coastline

$s_{O}=0.05$ represent the sample standard deviation for Orange Coast

$s_{C}=0.03$ represent the sample standard deviation for Coastline

$n_{O}=60$ sample size for Orange Coast

$n_{C}=60$ sample size for Coastline

$\alpha=0.005$ Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis: $\mu_{O} \geq \mu_{C}$

Alternative hypothesis: $\mu_{O} < \mu_{C}$

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

$t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=60+60-2=118$

Replacing the info we got:

$t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64$

Part e

We can calculate the p value with this probability:

$p_v =P(t_{118}$

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0

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The quotient of 2 times a number and 8

mojhsa [17]

Answer:

(2*x)/8 is the answer

Step-by-step explanation:

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Evaluate 3x^2 – 2xy - 4y^2

kykrilka [37]

Evaluate for x=2,y=−3

3(22)−(2)(2)(−3)−4(−3)2

= C. −12

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A bag contains 8 black beads and 4 white beads. If 2 beads are drawn at random, what is the probability that both beads are blac

maria [59]

Answer:

14/33

Step-by-step explanation:

The total amount of beads is 8+4 = 12. 8 of these are black beads, so that is what we want, so 8/12 or 2/3. For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11. Multiply this by 2/3 and we get 14/33.

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Write formula for arithmetic sequence when first term is not given

SashulF [63]

An<span> = am</span><span> + (n – 1)d.
i feel like this can work</span>

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