A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
Slope = (5 + 4)/(2 +1) = 9/3 = 3
y = mx + b
5 = 3(2) + b
b = -1
equation
y = 3x - 1
answer
y = 3x - 1
If you would like to find the quotient of 2 1/4 and 5/8, you can calculate this using the following steps:
2 1/4 = 9/4
2 1/4 / 5/8 = 9/4 / 5/8 = 9/4 * 8/5 = 18/5 = 3 3/5
The correct result would be 3 3/5.
Answer:
-8
Step-by-step explanation:
Y=mx+b, m=slope
in this case -8 is the m
Answer: THE ANSWER IS C
Step-by-step explanation:
