Ron was 8 hats.
4 are blue and 4 are red
8 - 4 = 4
Answer:
Step-by-step explanation:
If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes
I changed your x's to t's since t is for time.
Now we need to factor that quadratic and solve for time:
![0=-2(t^2-2t-8)](https://tex.z-dn.net/?f=0%3D-2%28t%5E2-2t-8%29)
Since -2 definitely does not equal 0, then
![t^2-2t-8=0](https://tex.z-dn.net/?f=t%5E2-2t-8%3D0)
Factor that and find t values of 4 and -2. Again, we know that time will never be negative, so
t = 4 seconds.
Answer:
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold
Step-by-step explanation:
Let p be the number of pies and c be the number of cakes.
Then according to given statement " the store sold 10 baked goods"
![c+p = 10\ \ \ Eqn\ 1](https://tex.z-dn.net/?f=c%2Bp%20%3D%2010%5C%20%5C%20%5C%20Eqn%5C%201)
And
"A cake costs $5 and a pie costs $4"
![5c+4p = 46\ \ \ \ Eqn\ 2](https://tex.z-dn.net/?f=5c%2B4p%20%3D%2046%5C%20%5C%20%5C%20%5C%20Eqn%5C%202)
Using equation 1,
![c=10-p](https://tex.z-dn.net/?f=c%3D10-p)
Putting this value of c in equation 2:
![5(10-p)+4p = 46\\50-5p+4p = 46\\-p = 46-50\\-p = -4\\p = 4](https://tex.z-dn.net/?f=5%2810-p%29%2B4p%20%3D%2046%5C%5C50-5p%2B4p%20%3D%2046%5C%5C-p%20%3D%2046-50%5C%5C-p%20%3D%20-4%5C%5Cp%20%3D%204)
Putting p = 4 in equation 1
![c+4 = 10\\c = 10-4\\c =6](https://tex.z-dn.net/?f=c%2B4%20%3D%2010%5C%5Cc%20%3D%2010-4%5C%5Cc%20%3D6)
Hence,
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold
The answer is C.7/3 pi ft lmk if you want more answers
Withdrew 1200
spent 1/5 on travel : 1/5(1200) = 1200/5 = 240
leaving her with : 1200 - 240 = 960
spent 2/3 on hardware : 2/3(960) = 1920/3 = 640
leaving her with : 960 - 640 = 320
320 - lunch = 300.50
320 - 300.50 = lunch
19.50 = lunch <==