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kozerog [31]
3 years ago
6

Ramona is counting the posts between mile markers on the highway. In 1 mile, she counts 33 posts if the posts are evenly spaced,

how many feet are they apart? (1 mile = 5,280 feet)
Mathematics
1 answer:
Yuri [45]3 years ago
6 0
5280/33 = 160 ft apart
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Jacob wants to make a graph to show the relationship between temperatures in Fahrenheit and degrees Celsius. He plots the follow
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Answer: It will not be spread out horizontally across the entire coordinate plane because in Step 2, Jacob plotted Fahrenheit instead of Celsius on the x-axis.

Jacob confused the values, the first coordinate of the ordered pairs (which corresponds to the x-axis) is in Celsius and he used it as Farenheit.

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3 years ago
The larger of two numbers is 10 less than twice the smaller number. if the sum of the two numbers is 38, find the tqo nubers
Iteru [2.4K]
Let two number A and B, and A >B

as we know A+10=2B① && A+B =38②

①-② solve that
B=16 so A=22

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3 0
3 years ago
I need help ASAP THANK YOU
Anestetic [448]

Answer:

see explanation

Step-by-step explanation:

To prove that BC ≅ AD, that is that BC = AD

You would need to prove the lengths are the same.

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3 years ago
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Use the Distributive Property of Multiplication over Addition to find each missing number.
Svet_ta [14]

Answer:

(3*9)+(3*6)

Step-by-step explanation:

7 0
2 years ago
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Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
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