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balu736 [363]
3 years ago
12

(b) As in part (a), how many three-digit phone prefixes are possible that do not start with 0 or 1, but contain 0 or 1 as the mi

ddle digit
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

The number of 3-digit phone prefixes that do not start with 0 or 1, but contain 0 or 1 as the middle digit is 160.

Step-by-step explanation:

The phone prefix for any area is of the form <u>X</u> <u>X</u> <u>X</u>.

These prefixes can take values from 0 to 9.

The condition to create a phone prefix is:

  • The first digit cannot be 0 or 1
  • The middle digit is either 0 or 1.

The possible number of ways to fill the first place is 8 since 0 or 1 cannot be the first digit.

The possible number of ways to fill the second place is 2 since the middle digit can be occupied by either 0 or 1.

The possible number of ways to fill the last place is 10 since there are no condition applied to the last digit.

Then the number of phone prefixes that can be formed is = 8\times2\times10=160

Thus, the possible number of phone prefixes possible is 160.

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Answer:

y = 35

Step-by-step explanation:

8 0
3 years ago
A jar that contains quarters and dimes is worth $7.15. If there are a total of 40 coins,
kherson [118]

Answer:

21 quarters and 19 dimes

Step-by-step explanation:

Create a system of equations where q is the number of quarters and d is the number of dimes.

0.25q + 0.1d = 7.15

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Solve by elimination by multiplying the bottom equation by -0.25

0.25q + 0.1d = 7.15

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7 0
3 years ago
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S is located at (9 -3) point T is located at (4 -3)
cupoosta [38]

Answer:

5

Step-by-step explanation:

The distance formula is:

d = \sqrt {\left( {x_2 - x_1} \right)^2 + \left( {y_2 - y_1} \right)^2 }

We can plug in the given coordinates into the equation:

d = \sqrt {\left( {4 - 9} \right)^2 + \left( {-3 - (-3)} \right)^2 }\\d = \sqrt {\left( {-5} \right)^2 + \left( {-3+3} \right)^2 }\\d = \sqrt{25 + \left( {0} \right)^2 }\\d=\sqrt{25+0}\\d=\sqrt{25}\\d=5

8 0
2 years ago
Which of the following sequences are convergent
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option A  and E

Step-by-step explanation:

Arithmetic sequence converge,  only  in the case only when r=0

otherwise , arithmetic sequence goes increasing or decreasing at a constant rate.

So we ignore second and fourth option

If |r|<1 then geometric sequence converge

if |r|>1 then geometric sequence diverge

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Answer is option A  and E




3 0
3 years ago
I NEED HELP NOW PLEASE
aleksandrvk [35]

Answer:

I think its 0.03 but I'm not a 100 percent sure

4 0
3 years ago
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