The answer is Angle T = angle N
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
So
bowl is a half sphere
cylinder is a cylninder
cone is cone
bowl:
area of circle=4/3 pi times r^3
half bowl=4/3 times 1/2 times pi times r^3=2/3pi r^3
cylinder=height times pi times radius^2
this cylinder=r times pi times r^2=pi times r^3
cone=1/3 times height times pi times radius^2
thgis cone=1/3 times r tiimes pi times r^2=1/3 times pi times r^3
compare
bowl=2/3 pi r^3
cylinder=pi r^3
cone=1/3 pi r^3
the cylinder is biggest
CYLINDER IS THE ANSWER
2.
sphwere=4/3 times radius^3 times pi
this sphere=4/3 times pi times r^3
cylinder=height times radius^2 time pi
this cylinder=2r times r^2 times pi=2r^3 times pi
cone=1/3 times height time r^2 times pi
this cone=1/3 times 2r times r^2 times pi=1/3 times 2r^3 times pi=2/3 times r^3 times pi
sphere:4/3 pi r^3
cylinder: 2 pi r^3
cone: 2/3 pi r^3
. you multiply all of the values in the parentesys.
Yes it is because -7+7=0 & 0+5=5 & 7+5=12