If you do the elimination process, here it is.
- A : Too small
+ B : I think so
- C : I little too big
- D : Way too big
Answer:
infinite
Step-by-step explanation:
B is one.
A < C and D are rational
Im thinking about E. It looks like a recurring decimal at first sight but I think its irrational.
13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0
Recall the double angle identity,
sin^2(x) = (1 - cos(2x))/2
If we let x = 13pi/12, then
sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]
where we took the negative square root because we expect a negative value.
Now, because cosine has a period of 2pi, we have
cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2
Then
sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]
sin(13pi/12) = - sqrt[2 - sqrt[3]]/2
The answer is D: 12
20 x 3 = 60
60 / 5 = 12