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3 years ago

9.

Mathematics

1 answer:

quester [9]3 years ago

7 0

Answer:

Step-by-step explanation:

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WILL GIVE BRAINLIEST WHAT IS THE FORMULA FOR SURFACE AREA

eimsori [14]

Answer:

Hi! The formula for surface area is:

area = 2lw + 2lh + 2hw

(l = length, w = width, h = height.)

<em>Hope this helps! :)</em>

8 0

3 years ago

Read 2 more answers

In△XYZ , XY¯¯¯¯¯¯=7in , YZ¯¯¯¯¯=5in , and XZ¯¯¯¯¯=4in . This triangle is reflected across the x-axis to result in △X'Y'Z' . Whic

ki77a [65]

Answer:

Step-by-step explanation:

Reflection is a transformation that preserves lengths.

Triangle XYZ, with side lengths XY = 7 in, YZ = 5 in, XZ = 4 in, is reflected across the x-axis to result in △X'Y'Z'.

This means that corresponding sides have the same lengths:

XY = X'Y' = 7 in;
XZ = X'Z' = 4 in;
YZ = Y'Z' = 5 in.

Find the perimeters of both triangles:

$P_{XYZ}=XY+XZ+YZ=7+4+5=16\ in\\ \\P_{X'Y'Z'}=X'Y'+X'Z'+Y'Z'=7+4+5=16\ in$

Hence, only option B is true.

8 0

3 years ago

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

4 years ago

Read 2 more answers

Find the probability of having 2,3, or 4

MrRissso [65]

Answer:

65.3%

Step-by-step explanation:

P(2,3, OR 4)

You have to do each one individually then add them together

5C2(.4)^2 times (.6)^3 + 5C3(.4)^3 times (.6)^3 + 5C4(.4)^4 times (.6)^1=

.3465+.2304+.0768=.6528=65.3%

5 0

3 years ago

Find the inverse of 2∛(x+2)

Artemon [7]

$y=2\sqrt[3]{x+2}\ \ \ |divide\ both\ sides\ by\ 2\\\\\sqrt[3]{x+2}=\dfrac{y}{2}\to x+2=\left(\frac{y}{2}\right)^3\ \ \ |subtract\ 2\ from\ both\ sides\\\\x=\dfrac{y^3}{2^3}-2\\\\x=\dfrac{1}{8}y^3-2\\\\\boxed{f(x)=2\sqrt[3]{x+2}\to f^{-1}(x)=\frac{1}{8}y^3-2}$

5 0

3 years ago