I believe that the length of AD to the nearest tenth would be 19.2 units long. If you have any questions, just ask me. ;)
Answer: 69
Step-by-step explanation: 50-30+40+9
<h3>
the answer is 2/3</h3>
Step-by-step explanation:
Answer:
B) x = 2, y = 3 and z = 5.
Step-by-step explanation:
3x −2y + 4z = 20 .....A
-x + 5y+ 12z = 73 .....B
x + 3y −2z = 1 ......C
Adding B and C:
8y + 10z = 74 .... E
Multiply equation B by -3:
-3x - 9y + 6z = -3
Add this equation to A:
-11y + 10z = 17
Subtract this equation fro E:
19y = 57
y = 3.
Substitute y = 3 in equation E:
8*3 + 10z = 74
10z = 50
z = 5.
Finally substitute y = 3 and z = 5 into equation C:
x + 3(3) - 2(5) = 1
x + 9 - 10 = 1
x = 1 + 1
x = 2.
Answer:
2.4 hours
Step-by-step explanation:
![\frac{1}{5} /\frac{1}{12}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D%20%2F%5Cfrac%7B1%7D%7B12%7D)
2.4 hours