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Citrus2011 [14]

3 years ago

7

A crab walk 1/12 of a mile an hour. The crab 1/5 of a mile away from the beach . How long will it take the crab to reach the bea

ch

1 answer:

marysya [2.9K]3 years ago

3 0

Answer:

2.4 hours

Step-by-step explanation:

$\frac{1}{5} /\frac{1}{12}$

2.4 hours

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In discus competition an athlete threw the discus 63.37meters 62.95 meters and 63.7meters order the distance from least to great

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62.95meters, 63.37meters, 63.7meters.

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3 years ago

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10. Make q the subject of the formula 5(q + p) = 4 + 8p

vichka [17]

The formula subject to q is $\frac{4+3p}{5}$

Explanation:

The given formula is $5(q+p)=4+8 p$

We need to determine the formula subject to q.

<u>The formula subject to q:</u>

The formula subject to q can be determined by solving the formula for q.

Let us solve the formula.

Thus, we have;

$5q+5p=4+8p$

Subtracting both sides by 5p, we have;

$5q=4+3p$

Dividing both sides by 5, we get;

$q=\frac{4+3p}{5}$

Thus, the formula subject to q is $\frac{4+3p}{5}$

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2 years ago

ANSWER ASAP PLS!!!

Dmitriy789 [7]

Answer:

From the points, the x coordinates are the same. With this similarity, the slope of the line would be undefined and it would result as an error to the point-slop formula of the line.

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3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

<em><u>Explanation</u></em>

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using <u>Cosine rule</u>, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

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Rama09 [41]

Answer:

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Step-by-step explanation:

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