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Julli [10]
3 years ago
6

The length of a rectangle is 2 yd longer than its width. if the perimeter of the rectangle is 40 yd , find its area.

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

perimeter = 2L+2W

L=2+w

40 = 2L+2W

40= 2(2+w)+2W

40=4+2w+2w

36=4w

w=9

L=9+2=11

2(9) = 18, 2(11) = 22, 22+18 = 40

L=11

W=9

 Area = L x w

area = 11x9= 99 square yards

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2 years ago
&lt; J and &lt; M are base angles of isosceles trapezoid JKLM. If measure &lt; J = 20x +9 and m &lt; M= 14x +15, find measure &l
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5 0
3 years ago
Tara has two standard, six-sided dice. If she rolls them 36 times, how many times should she expect a sum less than 5 to show up
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<span>So you'd expect a sum less than 5 six times. </span>
8 0
3 years ago
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