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3 years ago

For what frequencies does their sound at the speakers produce constructive interference?

1 answer:

5 0

You need to find the path difference. That is, how much further must sound waves from the more distant speaker travel than the close speaker, to reach the mike.
Use Pythagoras to find the distance of the further speaker: it is √(2.00²+4.50²)=4.924m so the path difference is 4.924-4.50=0.424m.
You will get constructive interference when this path difference is an integer number of wavelengths, because the waves will arrive at the mike in phase.
The speed of sound is 340m/s so the lowest frequency that will produce an antinode at the mike is the one that makes 0.424=λ
v=fλ so f=v/λ
f=340/0.424=801Hz.
The next one will be when 0.424m = 2λ => λ=0.212m
f=340/0.212=1602Hz
and so-on according to f=340n/0.424 where n is an integer.

For destructive interference the path difference must be (n-½)λ because that will make the waves arrive at the mike 180° out of phase.
f=340(n-½)/0.424

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3 years ago

A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe

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Answer:

$f_{fr}=1590.85 N$

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I hope it helps you!

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3 years ago

Master of physics needed

Delicious77 [7]

Hey JayDilla, I get 1/3. Here's how:
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$E_{linear}= \frac{1}{2}mv^2$
where
$v=r \omega$
giving
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The rotational part requires the moment of inertia of a solid cylinder
$I_{cyl} = \frac{1}{2}mr^2$
Then the rotational kinetic energy is
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Adding the two types of energy and factoring out common terms gives
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Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part. Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

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4 years ago

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