Answer:
i) 0.7
ii) 1.39
iii) 0.6
Next time, when compiling a Physics question, ensure you put the unit of each measurement.
Explanation:
i) T = time of flight = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting the values, we have: T = 
= 0.7
ii) distance travel = Range = R = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have: R = 
= 1.39
iii) Maximum Height = H = 
where u = speed = 4, A = 60 and g = acceleration due to gravity = 10 (It is a constant);
Subsituting values, we have: 
= 0.6
Answer:
<u>CHEMICAL CHANGE</u>:
A change in which one or more substances are converted into new substances is a <em>chemical change</em>.
<u>EXPLANATION:</u>
Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
<u>EXAMPLE:</u>
<em>Examples of Chemical Change in Everyday Life
</em>
Burning of paper and log of wood.
Digestion of food.
Boiling an egg.
Chemical battery usage.
Electroplating a metal.
Baking a cake.
Milk going sour.
Various metabolic reactions that take place in the cells.
Answer: The velocity of the ball is 30.0 m/s
This can be calculated by using the value of acceleration as 10.0 m/s2 in free fall and the given time of 3.0 seconds. To get the
velocity, one will have to multiply the acceleration with the given time and the
quotient would result to 30.0 m/s. Mostly all object regardless of their mass,
fall to earth with the same acceleration in the absence of air resistance and as
the child drops the ball from a window, it gains speed as it falls.
Answer: 2.04 s
Explanation:
Let the initial velocity be v, Angle of projectile be
Then the horizontal component = v cos θ = 16 m/s
Vertical component of velocity = v sin θ = 20 m/s
Time taken to reach the highest point is half the time taken for total flight.
Time for total flight,
Thus, the football takes 2.04 s to rise to the highest point of its trajectory.
