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lora16 [44]
3 years ago
10

The rainforest is hot, humid, and has frequent rainfall. In what way do the atmosphere and the hydrosphere contribute to this ty

pe of climate?
Physics
1 answer:
il63 [147K]3 years ago
7 0

Answer:

The atmosphere which contains nitrogen, oxygen, carbon dioxide, and other gases essential for life, contributes to the rainforest climate. The rainforest is hot, humid and helps balance the amount of carbon dioxide in the atmosphere by absorbing it and releasing more oxygen which is important for climate change.

The hydrosphere, which is the combination of various types of water sources and types found in air, in the form of water vapor; water found below the earth's surface and above, also contributes to the rainforest climate. The frequent rainfall dictates the vegetation growth in that area which also creates weather patterns due to the contribution of the atmosphere and the hydrosphere. The hydrosphere is important in the formation of rain. A  rainforest of frequent rainfall indicates a large amount of the combination of various types of water sources and types found in a particular area, which release the water back onto the rainforest.

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Rod AB has a diameter of 200mm and rod BC has a diameter of 150mm. Find the required temperature increase to close the gap at C.
Leni [432]

Answer:

T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}

Explanation:

The given data :-

  • Diameter of rod AB ( d₁ ) = 200 mm.
  • Diameter of rod BC ( d₂ ) = 150 mm.
  • The linear co-efficient of thermal expansion of copper ( ∝ ) = 1.6 × 10⁻⁶ /°C
  • The young's modulus of elasticity of copper ( E ) = 120 GPa = 120 × 10³ MPa.
  • Consider the required temperature increase to close the gap at C = T °C
  • Consider the change in length of the rod = бL

Solution :-

\begin{aligned}\sum H& =0\\-R_A+R_C&=0\\R_A&=R_C\\R_A&=R\\R_C&=R\\R_{A}&=\text{reaction\:force\:at\:A}\\R_{C}&=\text{reaction\:force\:at\:C}\\\sigma_{AB}&=\text{axial\:stress\:at\:A}\\\sigma_{BC}&=\text{axial\:stress\:at\:B}\\\sigma_{AB}&=\frac{R}{A_{A}}\\&=\frac{R_{A}}{A_{A}}\\\sigma_{BC}&=\frac{R_{B}}{A_{B}}\\&=\frac{R}{A_{B}}\\\frac{\sigma_{AB}}{\sigma_{BC}}&=\frac{A_{B}}{A_{B}}\\&=\frac{\frac{\pi}{4}\cdot 150^{2}}{\frac{\pi}{4}\cdot 200^{2}}\\&=\frac{9}{16}\end{aligned}

\begin{aligned}\delta L&= (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\0& = (\delta L _{thermal} +\delta L_{axial})_{AB} + ( \delta L _{thermal} +\delta L_{axial})_{BC}\\&=\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{AB}+\left[\alpha\:T\:L+\left(\frac{-RL}{AE}\right)\right]_{BC}\\&=2\:\alpha\:T\:L-\frac{L}{E}(\sigma_{AB}+\sigma_{BC})\\T&=\frac{\sigma_{AB}+\sigma_{BC}}{2\alpha E}\end{aligned}

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4 years ago
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Answer:

The Full Moon and New Moon

Explanation:

6 0
3 years ago
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And because of gravity it falls back down to the earth.
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It is gravity¿ what is the question?
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The speed of a boat in still water is 20 mph. it travels from one pier to another with the current in 4 hours and back against t
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The answer is, "the speed of the current is 5 miles per hour."

To calculate the speed of the current,
let's assume speed of current =  xmph. Time taken to travel from one pier to another with the current = 100/(20+x)h


But the time taken to travel from one pier to another with the current, which is given is = 4 hours. So,  4=100/(20+x) 80+4x = 100

4x = 20

x = 5 Thus, the speed of the current is 5 miles per hour.
3 0
3 years ago
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