We have that there is a formula connecting these three. V=I*R where V is voltage, I is the current and R is the resistance. Substituting, we get that V=210 Volta, which is the unit of measurement for voltage. You can think of the relationship in the following way : The energy of the field is equal to the flow of the field times the resistance that it meets.
The relationship between the masses of the object and the gravitational force between them is a direct relationship
Explanation:
The gravitational force between two objects is given by the equation:
where
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between them
We observe that:
- The gravitational force is proportional to the masses of the two objects, m1 and m2, so if the masses increase, the force will increase as well (so, this is a direct relationship)
- The gravitational force is inversely proportional to the square of the separation between the objects, so if the distance is increased, the force will decrease (so, this is an inverse relationship)
Learn more about gravitational force here:
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Let us take east and north as the positive x and y-axes should the motion be plotted in a cartesian plane. Thus, the x value is 45 miles and the y value is 20. The tangent of an angle is equal to the ratio of y to x.
tanθ = y / x
Substituting,
tanθ = 20/45 = 0.44
The value of θ is 23.96°.
I think it false. Sorry if i'm wrong.
Explanation:
We know that that the range of the ball on the earth
![R_{earth}=\frac{v_o^2sin2\theta}{g_{earth}}](https://tex.z-dn.net/?f=R_%7Bearth%7D%3D%5Cfrac%7Bv_o%5E2sin2%5Ctheta%7D%7Bg_%7Bearth%7D%7D)
therefore, range of the ball on moon
![R_{moon}=\frac{v_o^2sin2\theta}{g_{moon}}](https://tex.z-dn.net/?f=R_%7Bmoon%7D%3D%5Cfrac%7Bv_o%5E2sin2%5Ctheta%7D%7Bg_%7Bmoon%7D%7D)
![R_{moon}=\frac{v_o^2sin2\theta}{g_{earth}/12}](https://tex.z-dn.net/?f=R_%7Bmoon%7D%3D%5Cfrac%7Bv_o%5E2sin2%5Ctheta%7D%7Bg_%7Bearth%7D%2F12%7D)
therefore,
![R_{moon}=6R_{earth}](https://tex.z-dn.net/?f=R_%7Bmoon%7D%3D6R_%7Bearth%7D)
Therefore, the range of ball will be 6 times on the moon than that on earth