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Sever21 [200]
3 years ago
7

The first thing that made Trestail curious about the Crippen case was that __________.

Physics
1 answer:
Anna35 [415]3 years ago
7 0
Possibly the third one down. I don't think that DNA was around in Crippen's time. I'm not a criminologist or associated fun and games, though.
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Which one of the following acid-base imbalances? Arterial blood gas levels are obtained from the client. If the client’s results
nekit [7.7K]

Answer:

Explanation:

The correct answer is Metabolic alkalosis (D). A pH of 7.48 shows slight alkalinity, this normal concentration of Co2 in the blood ranges from 35 mmHg (millimetre Mercury) to 45 mmHg and the normal HCo3 ( Hydrogen trioxo carbonate ion) concentration ranges from 22mEq/L to 26mEq/L.

Therefor the patients pH level is high the Co2 level is normal and the HCo3 level is high. Hence, Metabolic alkalosis

7 0
3 years ago
Write the equation of motion gover the centre of mass<br><br><br>​
Nataly [62]

Answer:

write the equation of motion go over the centre of mass

Explanation:

the center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.

6 0
3 years ago
A hot air balloon must be designed to support a basket, cords, and one person for a total payload weight of 1300 N plus the addi
RSB [31]

Answer:

r = 4.44 m

Explanation:

 

For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid

         B = ρ g V

Now let's use Newton's equilibrium relationship

         B - W = 0

         B = W

The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)

         σ = W / A

         W = σ A

The area of ​​a sphere is

           A = 4π r²

       W = W₁ + σ 4π r²

The volume of a sphere is

           V = 4/3 π r³

Let's replace

     ρ g 4/3 π r³ = W₁ + σ 4π r²

If we use the ideal gas equation

     P V = n RT

    P = ρ RT

    ρ = P / RT

 

    P / RT g 4/3 π r³ - σ 4 π r² = W₁

    r² 4π (P/3RT  r - σ) = W₁

Let's replace the values

     r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000

     r² (11.81 r -0.060) = 13000 / 4pi

     r² (11.81 r - 0.060) = 1034.51

As the independent term is very small we can despise it, to find the solution

       r = 4.44 m

3 0
3 years ago
PWEESE HELPPPP I'LL GIVE BRAINLIEST, (NO LINKS OR I'LL REPORT)
miss Akunina [59]

Answer:

extensions.

Explanation:

Hope this helps

8 0
3 years ago
Read 2 more answers
A distance of 2.00 mm separates two objects of equal mass. If the gravitational force between them is 0.0104 N, find the mass of
Reptile [31]
F = \frac{gm,m2}{r2}
r = 0.002

0.0104 = \frac{(6.673 x  10^{-11} }{ 0.002)^{2} }

m = 25.0kg
4 0
3 years ago
Read 2 more answers
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