How do I solve 8/3=(y-9)/(7y+4)

Mathematics

1 answer:

zhuklara [117]3 years ago

3 0

Equation

$\dfrac{8}{3} = \dfrac{y - 9}{7y + 4}$ Cross Multiply

Solve

8 * (7y + 4) = 3*(y - 9) Remove the brackets

56y + 32 = 3y - 27 Subtract 3y from both sides.

56y - 3y + 32 = - 27

53y + 32 = -27 Subtract 32 from both sides.

53y = -32 - 27

53y = - 59 Divide by 53

y = - 59/53

y = - 1.113

Check

8/3 = (-1.113 - 9)/(7*-1.113 + 4)

8/3 = -10.113 / (- 7.791 + 4 )

8/3 = -10.113 / -3.791

8/3 = 2.667 which very nearly right. Some rounding has taken place.

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Check the picture below.

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8 0

3 years ago

Find "x"

Schach [20]

1. −2x−4=20+6x
Step 1: Simplify both sides of the equation.
−2x−4=20+6x
−2x+−4=20+6x
−2x−4=6x+20
Step 2: Subtract 6x from both sides.
−2x−4−6x=6x+20−6x
−8x−4=20
Step 3: Add 4 to both sides.
−8x−4+4=20+4
−8x=24
Step 4: Divide both sides by -8.
−8x/−8=24/−8
x=−3
Answer:
x=−3

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x=36
Answer:
x=36

4.
2(5x−1)=3x+5
Step 1: Simplify both sides of the equation.
2(5x−1)=3x+5
(2)(5x)+(2)(−1)=3x+5(Distribute)
10x+−2=3x+5
10x−2=3x+5
Step 2: Subtract 3x from both sides.
10x−2−3x=3x+5−3x
7x−2=5
Step 3: Add 2 to both sides.
7x−2+2=5+2
7x=7
Step 4: Divide both sides by 7.
7x/7=7/7
x=1
Answer:
x=1

5.
8−2(3x−4)+2x=5(x+6)+4
Step 1: Simplify both sides of the equation.
8−2(3x−4)+2x=5(x+6)+4
8+(−2)(3x)+(−2)(−4)+2x=(5)(x)+(5)(6)+4(Distribute)
8+−6x+8+2x=5x+30+4
(−6x+2x)+(8+8)=(5x)+(30+4)(Combine Like Terms)
−4x+16=5x+34
−4x+16=5x+34
Step 2: Subtract 5x from both sides.
−4x+16−5x=5x+34−5x
−9x+16=34
Step 3: Subtract 16 from both sides.
−9x+16−16=34−16
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Step 4: Divide both sides by -9.
−9x/−9=18/−9
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Answer:
x=−2

4 0

4 years ago

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leonid [27]

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4 years ago

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kkurt [141]

Answer:

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Step-by-step explanation:

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