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andrew-mc [135]
3 years ago
6

How do I solve 8/3=(y-9)/(7y+4)

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Equation

\dfrac{8}{3} = \dfrac{y - 9}{7y + 4} Cross Multiply

Solve

8 * (7y + 4) = 3*(y - 9) Remove the brackets

56y + 32 = 3y - 27 Subtract 3y from both sides.

56y - 3y + 32 = - 27

53y + 32 = -27 Subtract 32 from both sides.

53y = -32 - 27

53y = - 59 Divide by 53

y = - 59/53

y = - 1.113

Check

8/3 = (-1.113 - 9)/(7*-1.113 + 4)

8/3 = -10.113 / (- 7.791 + 4 )

8/3 = -10.113 / -3.791

8/3 = 2.667 which very nearly right. Some rounding has taken place.

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Step-by-step explanation:

<u>Binomial distribution formula:</u>

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[^1^5C_{10}(0.26)^1^0(1-0.26)^5]+[^1^5C_{11}(0.26)^1^1(1-0.26)^4]+[^1^5C_{12}(0.26)^1^2(1-0.26)^3]+[^1^5C_{13}(0.26)^1^3(1-0.26)^2]+[^1^5C_{14}(0.26)^1^4(1-0.26)^1]+[^1^5C_{15}(0.26)^1^5(1-0.26)^0]\\ \\ = 0.00094...+0.00015...+0.00001...+ 0.0000014...+ 0.000000071...+0.0000000016...\\ \\ =0.00111002... =0.111002...\% \approx 0.111\%


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Step-by-step explanation:

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