Question

How do I solve 8/3=(y-9)/(7y+4)

Answer 1

Equation

$\dfrac{8}{3} = \dfrac{y - 9}{7y + 4}$ Cross Multiply

Solve

8 * (7y + 4) = 3*(y - 9) Remove the brackets

56y + 32 = 3y - 27 Subtract 3y from both sides.

56y - 3y + 32 = - 27

53y + 32 = -27 Subtract 32 from both sides.

53y = -32 - 27

53y = - 59 Divide by 53

y = - 59/53

y = - 1.113

Check

8/3 = (-1.113 - 9)/(7*-1.113 + 4)

8/3 = -10.113 / (- 7.791 + 4 )

8/3 = -10.113 / -3.791

8/3 = 2.667 which very nearly right. Some rounding has taken place.