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Nostrana [21]
4 years ago
8

-3 over 4 +1 1 over 4 add using number line

Mathematics
1 answer:
Yuki888 [10]4 years ago
3 0

-19 im guessing hope the answer works

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Help show ur work pls I’d give brainly and thank yous to all ur awnsers
balandron [24]

Answer:

I don't know but maybe 3 in a half

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3 years ago
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Darian has $6000 to invest to save for college. He has two choices laid out in the table below. Will compound interest or simple
tatyana61 [14]

Answer:

C)There is not enough information to make a decision.

Step-by-step explanation:

simple interest

I= PRT

I = 6000* .07 * 6 = 2520


compound interest

I = P(1 + r/n) ^ nt

I = 6000(1 +

wait a minute

we don't know the compounding term

is it quarterly, annually, monthly??????


5 0
3 years ago
−4x+60<72 or 14x+11<−31 solve for x
gulaghasi [49]
The answer to your question is x = 8
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3 years ago
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If quadrilateral MNPO is reflected over the x-axis, what are the coordinates of
jenyasd209 [6]

<em>Note: you have not added the image, so I am assuming the quadrilateral MNOP with coordinates M(-4, 0), N(5, -3), P(2, 6) and O(-5, 7). It will anyhow clear your concept as I would explain the concept of reflection over the x-axis.</em>

Step-by-step explanation:

Considering the quadrilateral MNPO with assumed vertices

  • <em>M(-4, 0)</em>
  • <em>N(5, -3)</em>
  • <em>P(2, 6)</em>
  • <em>O(-5, 7)</em>

<em />

<em>THE RULE OF REFLECTION </em>states that when we tend to reflect a point let say (x, y), across the x-axis, the x-coordinate does not change or transform, but the y-coordinate is changed into its opposite sign i.e. (x,-y).

So, the coordinates of the point in the image after quadrilateral MNPO is reflected over the x-axis will be:

<h3>(x, y)                      (x, -y)</h3>

<em>M(-4, 0)                     M'(-4, 0)</em>

<em>N(5, -3)                     N'(5, 3)</em>

<em>P(2, 6)                      P'(2, -6)</em>

<em>O(-5, 7)                   O'(-5, -7)</em>

Hope, it will help you clear your concept regarding reflection of an object over the x-axis. Using this understanding, you can solve any other question related to this topic.

6 0
4 years ago
I need help with my math
Nat2105 [25]

Answer:

Part A. C=9

Part B. (w+3)² =139

Part C. w = 8.8 inch

Step-by-step explanation:

Given from the question length of the the picture = (2w+12) inches

Width of the picture = w inches

Area of the picture = 260 inch²

Part A. Area of the picture with the given dimensions= w×(2w+12)

Or w(2w+12) = 260

2w²+12w = 260

2(w²+6w) = 2×(130)

w²+6w = 130

Or w²+6w +9 = 130+9 ⇒ which is in the form of w²+6w+c = 130+c

Therefore for c = 9 we will get a perfect square trinomial.

Part B. As we have seen the equation in part A.

As required equation will be (w+3)²=139

Part C. Since (w+3)² = 139

Then by taking under root on both the sides of the equation

(w+3) =√139 = 11.8

(w+3)-3=11.8-3

w = 8.8 inch

3 0
3 years ago
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