A square has sides 5.6 cm.what is its perimeter

1 answer:

5 0

Squrae has 4 sides of equal legnth

perimiter=legnth of all sides added together or distance around (peri=around, meter=measure)

so 4 sides
each side is equal
1 sides=5.6
perimiter=5.6 times 4=22.4 cm is answer

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At time t = 0, a football player kicks a ball from the point A with position vector (2i + j) m on a horizontal football field. T

Strike441 [17]

Answer:

a) 9.434 m/s

b) i (2+5*t) + (1+8*t-4.905*t²) j

c) t= 8/5 secs

d) 3.598 m/s

e) See explanation

Step-by-step explanation:

Part a)

The speed of the ball can be calculated from the given velocity v = 5i +8j

Taking magnitude of v = 5i + 8j

magnitude (v) = $\sqrt{5^2 + 8^2}$ = 9.434 m/s.

Part b)

Using kinematic equation of particle as follows:

Sf = Si + Vi*t + 0.5*a*t² ..... Eq 1

Given: Si = (2i + j) m ; Vi = (5i+8j) m/s; a = -9.81 j m/s²

We evaluate Eq 1:

Sf = (2i+j) + (5i+8j)*t + 0.5*(-9.81j)*t²

We get after combining similar terms:

Sf = i (2+5*t) + (1+8*t-4.905*t²) j ..... Eq 2

Part c)

Using kinematic equation of particle only in i axis as follows we use Eq 1:

Sf = Si + Vi*t + 0.5*a*t²

Given: Si = 2 m ; Sf = 10; Vi = 5 m/s; a = 0;

We evaluate Eq 1:

10 = 2 + 5*t - Solve for t

t = 8/5 seconds

Note: The above is the time t when the ball is due north of (10i+7j) i.e having a position vector of 10 in east direction but unknown in north direction. A point directly above or below 10i + 7j.

Part d)

The interception of ball and the player occurs at the same t = 8/5 secs and @ position vector (10i + aj) where a is a constant needs to be found.

Find a:

Using Eq 2 found in part b:

Sf = i (2+5*t) + (1+8*t-4.905*t²) j

Evaluate @ t= 8/5 secs

Sf = (10) i + (1.2432) j .... Eq 3

To find the speed v of the player when he intercepts the ball at Sf = (10) i + (1.2432) j is evaluated as follows:

v = change in position of player / Time

$v =\frac{Eq 3 - (10i+7j)}{1.6}$