What is the product of 9 and -7?

What is the measurement of the longest line segment in a right rectangular prism that is 26 inches long, 2 inches wide, and 2 in

EastWind [94]

Answer:

$6\sqrt{19} \approx 26.153$ inches.

Step-by-step explanation:

The longest line segment in a right rectangular prism is the diagonal that connects two opposite vertices. On the first diagram attached, the green line segment connecting A and G is one such diagonals. The goal is to find the length of segment $\mathsf{AG}$ .

In this diagram (not to scale,) $\mathsf{AB} = 26$ (length of prism,) $\mathsf{AC} = 2$ (width of prism,) $\mathsf{AE} = 2$ (height of prism.)

Pythagorean Theorem can help find the length of $\mathsf{AG}$ , one of the longest line segments in this prism. However, note that this theorem is intended for right triangles in 2D, not the diagonal in a 3D prism. The workaround is to simply apply this theorem on two different right triangles.

Start by finding the length of line segment $\mathsf{AD}$ . That's the black dotted line in the diagram. In right triangle $\triangle\mathsf{ABD}$ (second diagram,)

Segment $\mathsf{AD}$ is the hypotenuse.
One of the legs of $\triangle\mathsf{ABD}$ is $\mathsf{AB}$ . The length of $\mathsf{AB}$ is $26$ , same as the length of this prism.
Segment $\mathsf{BD}$ is the other leg of this triangle. The length of $\mathsf{BD}$ is $2$ , same as the width of this prism.

Apply the Pythagorean Theorem to right triangle $\triangle\mathsf{ABD}$ to find the length of $\mathsf{AB}$ , the hypotenuse of this triangle:

$\mathsf{AD} = \sqrt{\mathsf{AB}^2 + \mathsf{BD}^2} = \sqrt{26^2 + 2^2}$ .

Consider right triangle $\triangle \mathsf{ADG}$ (third diagram.) In this triangle,

Segment $\mathsf{AG}$ is the hypotenuse, while
$\mathsf{AD}$ and $\mathsf{DG}$ are the two legs.

$\mathsf{AD} = \sqrt{26^2 + 2^2}$ . The length of segment $\mathsf{DG}$ is the same as the height of the rectangular prism, $2$ (inches.) Apply the Pythagorean Theorem to right triangle $\triangle \mathsf{ADG}$ to find the length of the hypotenuse $\mathsf{AG}$ :

$\begin{aligned}\mathsf{AG} &= \sqrt{\mathsf{AD}^2 + \mathsf{GD}^2} \\ &= \sqrt{\left(\sqrt{26^2 + 2^2}\right)^2 + 2^2}\\ &= \sqrt{\left(26^2 + 2^2\right) + 2^2} \\&= 6\sqrt{19} \\&\approx 26.153\end{aligned}$ .

Hence, the length of the longest line segment in this prism is $6\sqrt{19} \approx 26.153$ inches.

5 0

3 years ago

3# Find the missing variable (s). Round to the nearest tenth.

rewona [7]

Answer:

Step-by-step explanation:

This triangle is already positioned to match trig functions (also known as circular functions).

Point A is origin, side AC (length x) is on X axis,

side CB (length y) is parallel to Y axis.

***** You just remember *****

cos is horizontal, on X axis,

sin is vertical, on Y axis.

To get from unit triangle with hypotenuse 1,

horizontal side cos(θ), vertical side sin(θ), you multiply all sides by same number, namely, the specified length of the hypotenuse.

***** that's all you need to know *****

Draw a unit circle centered at A, mark point Y at intersection of circle and AB, and drop a vertical line from Y crossing X axis at X.

Then radial segment AY is 1, AB is 10

horizontal segment AX is cos(32°), AC is 10AX

vertical segment XY is sin(32°), CB is 10XY.

So x = 10 cos(32°), y= 10 sin(32°).

7 0

3 years ago

18. Solve the inequality. Show your work.<br> –6b > 42 or 4b > –4

grigory [225]

-6b > 42 = b<-7
or
4b > -4 = b>-1
Hope this helps.

6 0

3 years ago

Read 2 more answers

SOMEBODY HELPPPPPPPPPP BE FAST

Paul [167]

The answer 30, 40, 50

Forms a right triangle

Hope this helps!

5 0

2 years ago

Chris paid $36 for 3 tanktops and 2 shirts. a shirt cost 3 times as much as a tank top. how much did chris pay for the 2 shirts?

devlian [24]

Answer:

$72

Step-by-step explanation:

36/3=12

1 tanktop=$12

12*3=36

1 shirt equals=$36

36*2=72

2 shirts=$72

4 0

3 years ago