Direction vector of line of intersection of two planes is the cross product of the normal vectors of the planes, namely
p1: x+y+z=2
p2: x+7y+7z=2
and the corresponding normal vectors are: (equiv. to coeff. of the plane)
n1:<1,1,1>
n2:<1,7,7>
The cross product n1 x n2
vl=
i j l
1 1 1
1 7 7
=<7-7, 1-7, 7-1>
=<0,-6,6>
Simplify by reducing length by a factor of 6
vl=<0,-1,1>
By observing the equations of the two planes, we see that (2,0,0) is a point on the intersection, because this points satisfies both plane equations.
Thus the parametric equation of the line is
L: (2,0,0)+t(0,-1,1)
or
L: x=2, y=-t, z=t
Answer:
addition
Step-by-step explanation:
in this case its addition , but the only reson it is going first is bc it sin the parenthasies
Answer:
Answer: -18 + -3h
More simple: -18 - 3h
Step-by-step explanation:
- -3 × 6 = -18
- -3 × h = -3h
- Put them together: -18 + -3h
Answer:=3a+2b−21
Step-by-step explanation:
Let's simplify step-by-step.
3a+2b−7−4−10
=3a+2b+−7+−4+−10
Combine Like Terms:
=3a+2b+−7+−4+−10
=(3a)+(2b)+(−7+−4+−10)
=3a+2b+−21
