Standard form is x + y = number.
y = -2/5 x
y + 2/5 x = 0
2/5 x + y = 0
In standard form, the coefficient of x or y cannot be a fraction.
Therefore we have to multiply the whole equation by 5.
2x + 5y = 0
Jenny pencil is as long as a giraffe's neck.
Answer:
The probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Step-by-step explanation:
Denote the events as follows:
<em>X</em> = an elementary or secondary school teacher from a city is a female
<em>Y</em> = an elementary or secondary school teacher holds a second job
The information provided is:
P (X) = 0.66
P (Y) = 0.46
P (X ∩ Y) = 0.22
The addition rule of probability is:
Use this formula to compute the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job as follows:
Thus, the probability that an elementary or secondary school teacher selected at random from this city is a female or holds a second job is 0.90.
Answer:
a) -7/9
b) 16 / (n² + 15n + 56)
c) 1
Step-by-step explanation:
When n = 1, there is only one term in the series, so a₁ = s₁.
a₁ = (1 − 8) / (1 + 8)
a₁ = -7/9
The sum of the first n terms is equal to the sum of the first n−1 terms plus the nth term.
sₙ = sₙ₋₁ + aₙ
(n − 8) / (n + 8) = (n − 1 − 8) / (n − 1 + 8) + aₙ
(n − 8) / (n + 8) = (n − 9) / (n + 7) + aₙ
aₙ = (n − 8) / (n + 8) − (n − 9) / (n + 7)
If you wish, you can simplify by finding the common denominator.
aₙ = [(n − 8) (n + 7) − (n − 9) (n + 8)] / [(n + 8) (n + 7)]
aₙ = [n² − n − 56 − (n² − n − 72)] / (n² + 15n + 56)
aₙ = 16 / (n² + 15n + 56)
The infinite sum is:
∑₁°° aₙ = lim(n→∞) sₙ
∑₁°° aₙ = lim(n→∞) (n − 8) / (n + 8)
∑₁°° aₙ = 1
One way is to find common factors
example
8/6=4/3 because 8/6, 8 and 6 have common factor of 2 so divide that out to get 4/3
basically divide the LCM from each
so factor
we can combine 36m-48m into -12m
we have
-12m/6m
common factor is 6m
-12m/6m=(-2)/1 times (6m)/(6m)=-2 times 1=-2
answer is -2
