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I am Lyosha [343]
3 years ago
11

In arithmetic sequence the first term is 5 and the common difference is 4. Determine the 6th term of sequence

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

The 6th term of the sequence is 25

Step-by-step explanation:

first term = a = 5

common difference = d = 4

The nth term of a sequence is

T_n = a + (n - 1)d

Therefore, the 6th term of the sequence is

T_6 = a + (6 - 1)d

T_6 = a + 5d

T_6 = 5 + 5(4)

T_6 = 5 + 20

T_6 = 25

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Y=-2x+5<br> X | Y<br> ____<br> 5<br> -1<br> 2<br> 0
Y_Kistochka [10]

Answers:

<h3>1. -5</h3><h3>2. 7</h3><h3>3. 1</h3><h3>4. 5</h3>

Step-by-step explanation:

Plug in the x into the equation and solve.

<h3>Value 1: X = 5</h3>

Y = -2(5) + 5

Y = -10 + 5

Y = -5

<h3>Value 2: X = -1</h3>

Y = -2(-1) + 5

Y = 2 + 5

Y = 7

<h3>Value 3: X = 2</h3>

Y = -2(2) + 5

Y = -4 + 5

Y = 1

<h3>Value 4: X = 0</h3>

Y = -2(0) + 5

Y = 0 + 5

Y = 5

I'm always happy to help :)

8 0
3 years ago
Fuel for the reasearch vessels will be stored in a cylindrical tank with a radius of 10 meters and a height of 5 meters. Using a
Lemur [1.5K]

The volume of the tank is 1570 cubic meters

<h3>How to determine the volume</h3>

The formula for determining the volume of a cylinder is expressed as;

Volume = πr²h

Where;

  • radius is 10 meters
  • height is 5 meters
  • pi = 3. 14

Now, let's substitute into the formula;

Volume = 3. 14 × 10² × 5

Volume = 3. 14 × 100 × 5

Multiply through

Volume = 1570 cubic meters

Thus, the volume of the tank is 1570 cubic meters

Learn more about volume here:

brainly.com/question/1972490

#SPJ1

6 0
2 years ago
Jonathan purchased 4 shirts, 2 jackets, and 3 pants. How many different outfits using a
vagabundo [1.1K]

Answer:

24 way im pretty sure

Step-by-step explanation:

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3 years ago
The volume of a solid is measured in units cubed. True False
weeeeeb [17]
I think the answer would be true
4 0
3 years ago
Read 2 more answers
Let f(x)=x^3 and g(x)= √x, and h(x)=x/3. Find each of the following: f(g(h(6)))
rewona [7]

Answer:

go from inside out.

h(x)=x/3

(\sqrt{2})^{3}=> h(6) = 6/3 = 2

g(x) = \sqrt{x}

=> g(h(6)) = g(2) = \sqrt{2}

f(x) = x^{3}

=> f(g(h(6))) = f(\sqrt{2} ) = (\sqrt{2} )^{3}

6 0
3 years ago
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