For this case, the first thing we must take into account is the following definition:
d = v * t
Where,
d: distance
v: speed
t: time
Substituting values we have:
Trip 1:
50 = v * t1
We cleared t1:
t2 = (50) * (1 / v)
Trip 2:
300 = (3 * v) * t2
We cleared t2:
t2 = (300/3) * (1 / v)
t2 = (100) * (1 / v)
Rewriting:
t2 = 2 (50) * (1 / v)
t2 = 2 * t1
Answer:
His new time compared with the old time was:
Twice the old time.
t2 = 2 * t1.
5 1.2
-3 7
6 1.2
2 -3
yes its a function, as long as the domain (input) doesnt have the same number with two different ranges (outputs) its a function
<span>3x + 8x + 4x = 6x + 63
15x = 6x + 63
9x = 63
x = 7
so
5x+ 23 =5(7) + 23 = 35+23 = 58</span>
Step-by-step explanation:
3d=dx3
3x12=36
50-36=14
