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Serjik [45]
3 years ago
12

What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

Mathematics
1 answer:
Komok [63]3 years ago
8 0
Hi there! The answer is n = 10.

(2 {x}^{9}  {y}^{n} )(4 {x}^{2}  {y}^{10} ) = 8 {x}^{11}  {y}^{20}

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
{x}^{9}  \times  {x}^{2}  =  {x}^{9 + 2}  = x {}^{11}

The powers of y work the same way.
{y}^{n}  \times  {y}^{10}  =  {y}^{n + 10}  =  {y}^{20}

Hence, n = 10, since
{y}^{10 + 10}  =  {y}^{20}
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