1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Serjik [45]
3 years ago
12

What value of n makes the equation true? (2x^9y^n)(4x^2y^10)=8x^11y^20

Mathematics
1 answer:
Komok [63]3 years ago
8 0
Hi there! The answer is n = 10.

(2 {x}^{9}  {y}^{n} )(4 {x}^{2}  {y}^{10} ) = 8 {x}^{11}  {y}^{20}

As you see at the powers of x, we need to add the exponents of the power we when multiply them.
{x}^{9}  \times  {x}^{2}  =  {x}^{9 + 2}  = x {}^{11}

The powers of y work the same way.
{y}^{n}  \times  {y}^{10}  =  {y}^{n + 10}  =  {y}^{20}

Hence, n = 10, since
{y}^{10 + 10}  =  {y}^{20}
You might be interested in
You walk east 720 feet to get from your house to class. After class, you walk southwest 1,044 feet to meet your friends for lunc
strojnjashka [21]
The direction you are traveling to get back home is North
4 0
3 years ago
Tan^2 A/1+cot^2 A + cot^2 A/1+tan^2 A=sec^2 A cosec^2 A-3
omeli [17]
\frac{tan^2x}{1+cot^2x}+\frac{cot^2x}{1+tan^2x}=sec^2x\ cosec^2x-3\\\\L=\frac{tan^2x(1+tan^2x)+cot^2x(1+cot^2x)}{(1+cot^2x)(1+tan^2x)}=\frac{tan^2x+tan^4x+cot^2x+cot^4x}{1+tan^2x+cot^2x+tanxcotx}\\\\=\frac{tan^2x+cot^2x+tan^4x+cot^4x}{1+tan^2x+cot^2x+1}=\frac{tan^2x+2+cot^2x+tan^4x-2+cot^4x}{tan^2x+cot^2x+2}

=\frac{(tanx+cotx)^2+(tan^2x-cot^2x)^2}{(tanx+cotx)^2}=\frac{(tanx+cotx)^2}{(tanx+cotx)^2}+\frac{(tan^2x-cot^2x)^2}{(tanx+cotx)^2}\\\\=1+\frac{(tanx-cotx)^2(tanx+cotx)^2}{(tanx+cotx)^2}=1+(tanx-cotx)^2\\\\=1+tan^2x-2tanx\ cotx+cot^2x=tan^2x+cot^2x+1-2\\\\=\left(\frac{sinx}{cosx}\right)^2+\left(\frac{cosx}{sinx}\right)^2-1=\frac{sin^2x}{cos^2x}+\frac{cos^2x}{sin^2x}-1=\frac{sin^4x+cos^4x}{sin^2x\ cos^2x}-1

=\frac{(sin^2x)^2+2sin^2x\ cos^2x+(cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{(sin^2x+cos^2x)^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1^2-2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1\\\\=\frac{1}{sin^2x\ cos^2x}-\frac{2sin^2x\ cos^2x}{sin^2x\ cos^2x}-1=\frac{1}{sin^2x}\cdot\frac{1}{cos^2x}-2-1\\\\=cosec^2x\cdot sec^2x-3=sec^2x\ cosec^2x-3=R
3 0
3 years ago
If n=6 and x=1/6, then n(2-x)=
scoundrel [369]

Answer:

11

Step-by-step explanation:

4 0
3 years ago
Please help me understand how to solve this(include steps)
Sidana [21]
I will say it is 8/4 if you simplified  8/4 by 4 it will be 2/1.
5 0
3 years ago
A bag with 8 marbles is shown below. (The 8 marbles are red.) A marble is
Degger [83]

Answer:

1

Step-by-step explanation:

There are 8 marbles.

All marbles are red.

p(red) = 8/8 = 1

Answer: 1

6 0
2 years ago
Read 2 more answers
Other questions:
  • What is the product of​
    12·2 answers
  • Can Someone help with problems 2,3,4. Please
    9·1 answer
  • What is 5 = p over 4
    9·1 answer
  • What are all the exact solutions of -3tan^2x+1=0? Give your answers in radians.
    15·1 answer
  • The time is takes to build a skyscraper is proportional to its height and inversely proportional to the number of construction w
    14·1 answer
  • Idc about giving away my points...How about 20+ Points for explanation & Correct answer
    5·1 answer
  • Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following
    15·2 answers
  • What figure is shown in the drawing ? JH , JK , EJ , EK
    10·1 answer
  • four out of nine dogs weigh less than 20 pounds.What is the decimal equivalent for the number of dogs weighing under 20 pounds.
    12·1 answer
  • Can you help me with question number 10, please?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!