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Free_Kalibri [48]
3 years ago
7

The weight of a cup filled with water is 2.58kg The weight of the empty cup is 1.5 kg. Considering significant figures what is w

eight of the water
Chemistry
1 answer:
Finger [1]3 years ago
6 0

Explanation:

ja, you have to be to work i

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A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could
monitta

Answer:

b. HCOOH/ NaHCOO.

Explanation:

A buffer system may be formed in one of two forms:

  • A weak acid with its conjugate base.
  • A weak base with its conjugate acid.

Chose the pairs below that you could use to make a buffered solution.

a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.

b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.

c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.

d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.

7 0
2 years ago
Under certain conditions the rate of this reaction is zero order in ammonia with a rate constant of ·0.0020Ms−1 : 2NH3 (g)→N2 (g
RSB [31]

Answer:250

Explanation:

7 0
3 years ago
Read 2 more answers
How many atoms are there in 7.80 moles of germanium
Orlov [11]
<h3>Answer:</h3>

4.70 × 10²⁴ atoms Ge

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

7.80 mol Ge

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

\displaystyle 7.80 \ mol \ Ge(\frac{6.022 \cdot 10^{23} \ atoms \ Ge}{1 \ mol \ Ge} ) = 4.69716 × 10²⁴ atoms Ge

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.69716 × 10²⁴ atoms Ge ≈ 4.70 × 10²⁴ atoms Ge

8 0
2 years ago
What is the Lewis Dot Diagram of gold?
ratelena [41]
Its structure is Au with one dot on top
6 0
3 years ago
What is the volume of 0.250 m hydrochloric acid required to react completely with 20.0 ml of 0.250 m ca(oh)2?
Soloha48 [4]
The balanced equation for the above neutralisation reaction is as follows;
Ca(OH)₂ + 2HCl ----> CaCl₂ + 2H₂O
Stoichiometry of Ca(OH)₂ to HCl is 1:2
number of Ca(OH)₂ moles reacted - 0.250 mol/L x 20.0 x 10⁻³ L = 5.00 x 10⁻³ mol
according to molar ratio of 1:2
number of HCl moles required = 2 x number of Ca(OH)₂ moles reacted
number of HCl moles = 5.00 x 10⁻³ x 2 = 10.0 x 10⁻³ mol
molarity of HCl solution - 0.250 M
there are 0.250 mol  in volume of 1 L
therefore 10.0 x 10⁻³ mol in - 10.0 x 10⁻³ mol  / 0.250 mol/L = 40.0 mL 
40.0 mL of 0.250 M HCl is required
5 0
3 years ago
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