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faltersainse [42]
3 years ago
8

Convert 15.78 g of H2O2 to mols. Convert 15.3 mols Au to g

Chemistry
1 answer:
iren2701 [21]3 years ago
8 0

Answer:

.46 moles H2O2

3,014 grams Au

Explanation:

H2O2:

15.78g (1 mol/34g) = .46 moles H2O2

Au:

15.3mol (197g/mol) = 3,014 grams Au

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Which amino acid(s) are metabolites in the urea cycle, but are not used as building blocks of proteins? A) Ornithine B) Citrilli
In-s [12.5K]

Answer:

D)

Explanation:

Ornithine and Citrulline are the amino acids which are metabolites in the urea cycle but not used as building blocks of proteins.

Ornithine is the most important reactant in urea cycle that is responsible for 80% of the excretion of nitrogen in the body. It even improves liver function.

Even Citrulline is not used in the building blocks of protein, Citrulline is mainly used to widen blood vessels and may play a role in muscle building.

3 0
3 years ago
0. 820 mole of hydrogen gas has a volume of 2. 00 l at a certain temperature and pressure. What is the volume of 0. 125 mol of t
Mamont248 [21]

The volume of 0.125 mole of the gas at the same temperature and pressure 0.30 L

<h3>Data obtained from the question </h3>
  • Initial mole (n₁) = 0.82 mole
  • Initial volume (V₁) = 2 L
  • New mole (n₂) = 0.125 mole
  • Pressure = Constant
  • Temperature = Constant
  • New Volume (V₂) =?

<h3>How to determine the new volume</h3>

The new volume can be obtained as illustrated below

PV = nRT

Divide both side by P

V = nRT / P

Divide both side by n

V / n = RT / P = Constant

Thus,

V₁ / n₁ = V₂ / n₂

2 / 0.82 = V₂ / 0.125

Cross multiply

0.82 × V₂ = 2 × 0.125

Divide both side by 0.82

V₂ = (2 × 0.125) / 0.82

V₂ = 0.30 L

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ12

4 0
2 years ago
Why are being flammable and combustible considered to be chemical properties and not physical properties?
g100num [7]

Answer:

C. They change the substance into another substance.

Explanation:

Hope it helps!!

6 0
3 years ago
Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and
sammy [17]

Answer:

The answer is explained below:

Explanation:

Given the chemical equation:

                   N2H4(g)+H2(g)→2NH3(g)

The standard enthalpy of formation is given by the following formula:

            ΔH^0 rxn = ∑ B reactants - ∑ product

       -187.78 kJ/mol = [( 1x B N-N) + (1 x B N-H ) + (1 x b H-H)] - [ 6 x B N-H]

       -187.78 kJ/mol = [( 1x B N-N)  +(4 x 391 kJ/mol) + (1 x 436  kJ/mol)] - [ 6x 391  kJ/mol ]

        -187.78 kJ/mol =  B N-N  + (1564 + 436 - 2346) kJ/mol

                                       B   = 158.22 kJ/mol

So, in this case the enthalpy of N-N bond is 158 kJ/mol

6 0
3 years ago
Concentrations expressed as a percent by mass are useful when the solute is a _____.
Westkost [7]

C. Solid

Although molarity is commonly used to express concentrations for reactions in solution or for titrations, it does have one drawback—molarity is the number of moles of solute divided by the volume of the solution, and the volume of a solution depends on its density, which is a function of temperature.

3 0
3 years ago
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