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DiKsa [7]
2 years ago
7

An ant looks to the top of a bulding at an angle of elevation of 32°. The ant then walks an additional 66 feet from the edge of

the building. If the new angle of elevation from the ant to the top of the building is 22°, find the height of the building. Round to the nearest tenth
Mathematics
1 answer:
Keith_Richards [23]2 years ago
8 0
Let the height of the building be x. Let the initial distance of the ant from the building be y, then
tan 32 = x/y
y = x/tan 32 . . . . . . . . (1)
tan 22 = x/(y + 66)
y tan 22 + 66 tan 22 = x
y = (x - 66 tan 22)/tan 22 . . . . . . . . (2)
Equating (1) and (2), we have
x/tan 32 = (x - 66 tan 22)/tan 22
x tan 22 = x tan 32 - 66 tan 22 (tan 32)
x(tan 32 - tan 22) = 66 tan 22 (tan 32)
x = (66 tan 22 (tan 32))/(tan 32 - tan 22) = 66(0.4040)(0.6249)/(0.6249 - 0.4040) = 16.6626/0.2208 = 75.4

Therefore, the height of the building is 75.4 feet.
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Step-by-step explanation:

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4 0
2 years ago
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1. The length of a rectangle is 5 mm longer than its width. Its perimeter is more than 30 mm. Let w equal the width of the recta
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The of the rectangle is w > 5mm
4 0
3 years ago
The figure is made up of two identical quarter circles and a rectangle. The length of the rectangle is 35 cm and its breadth is
Ymorist [56]

Area of the middle rectangular section = length x width = 35 x 20 = 700 square cm.

The radius of the circular sections is 25 cm

Area of a full circle is pi x r^2 = 3.14 x 25^2 = 1962.5 square cm.

There are two quarter circles which is 1/2 of a circle. The area of those would be 1962.5/2 = 981.25 square cm.

Total area of the figure = 700 + 981.25 = 1681.25 square cm

6 0
2 years ago
Two forces with magnitudes of 100 and 50 pounds act on an object at angles of 50° and 160°, respectively. Find the direction and
shusha [124]
Forces in direction x:
 
fx1 = 100 * cos (50) = 64.28
 fx2 = 50 * cos (160) = - 46.99
 The resultant is:
 fx = fx1 + fx2 = 17.29

 Forces in direction y:
 
fy1 = 100 * sine (50) = 76.60
 fy2 = 50 * sine (160) = 17.10
 The resultant is:
 fy = fy1 + fy2 = 93.70
 The magnitude of the resulting force is:
 
f = root (fx ^ 2 + fy ^ 2)
 f = root ((17.29) ^ 2 + (93.70) ^ 2)
 f = 95.28
 The angle is:
 
theta = atan (fy / fx)
 theta = atan (93.70 / 17.29)
 theta = 79.55 degrees
 Answer:
 
The direction and magnitude of the resultant force are:
 
f = 95.28 pounds at theta = 79.55 degrees
6 0
2 years ago
I need to find how many solutions does the system have. ​
REY [17]
From what I got there is one real solution :)

Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)

Also they are both straight line graphs so they will either have one or no solutions

Hope this helped :)
4 0
3 years ago
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