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3 years ago

Fiona draws a circle with a diameter of 14 meters. What is the area of Fiona’s circle?

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

4 0

Answer:

A ≈ 153.94 meters

Step-by-step explanation:

area area equals pi r squared. radius is half of the diameter. Half of 14 meters is 7 meters.

7 meters pi r squared is about 153.94 meters.

that would be my answer

Schach [20]3 years ago

4 0

Answer:

The area of the circle is $153.94meters^2$

Step-by-step explanation:

The formula for the area of a circle is : $\pi *radius^{2}$

To work this out you would first need to divide the diameter of 14 by 2, this gives you 7. This is in order for us to calculate the radius. The radius of a circle is the length from one side to the centre.

Now that we know the radius the next step is to multiply pi by the radius of 7 squared, this gives you 153.94. This is because in order for you to calculate the area you would substitute the values into the formula.

1) Divide 14 by 2.

$14/2=7$

2) Multiply pi by 7 squared.

$\pi *7^2=153.94 meters^2$

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See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are $v_1, v_2 and l(v)$ .

We assume that the edges from the begin are the incoming edges of $v_1$ and all the outgoing edges from v are outgoing edges from $v_2$

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For every $v \in V$ we create 2 vertices $v_1, v_2 \in V'$

Now we can add a new edge asscoiated to $v_1, v_2 \in E'$ with the condition $a' (v_1,v_2) = l(v)$

Now for each edges $(u,v)\in E$ we can create the following edge $( u_r, v_1) \in E'$ and the capacity is given by: $a' (u_r, v_1) = a (u,v)$

And for this case we can see this:

$|V'| = 2|V|, |E'|= |E| +|V|$

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge $(u,v) \in G$ we can assume that $x' (u_r ,v_1) = x(u,v)$

Then for each vertex $u \in V -t$ and we can define $x\(u_1,u_r) = \sum_{v \in V} x(u,v)$ and $x' (t_1,t_2) = \sum_{v \in V} x(v,t)$

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form $(u_r, u_1)$ we have a corresponding edge in G because: