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3 years ago

Please help me with problem 2 of graphs

Mathematics

2 answers:

m_a_m_a [10]3 years ago

7 0

You are going down 1 (which is minus and going in the y direction) and to left 4 is is also minus in the x direction.
(-4 , -1) Using x as the criteria only A and C have a chance. A is incorrect, because goes up one unit over the x axis.
C <<<<< answer.

Zarrin [17]3 years ago

6 0

Hello!

First you have to find point h.

The you go from the center can count how many spaces over you go

Since you go 4 to the left the first number is -4

Then you count how many spaces you go up or down

Since you goes down once the second number is -1

So the answer is (-4, -1)

Hope this helps!

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2/9 x __ = 3/15. 2/5 x __ = 7/12.

vodka [1.7K]

Answer:

1 x= 9/10 or 0.9

2 x= 35/24 or 1 11/24

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3 years ago

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stira [4]

Answer:

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3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

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3 years ago

Write the equation for a line that passes through the point (2,5) and a slope of m =10 in point slope form

wlad13 [49]

Answer:

y=10x-15

Step-by-step explanation:

with the points given you know x=2 and y=5

make a new point called (x,y)

now use the formula (y-5)/(x-2)=10 (10 being the gradient)

y-5 = 10(x-2)

y-5=10x-20

add 5 to both sides

y-5+5=10x-20+5

y=10x-15

8 0

3 years ago

Read 2 more answers

Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10

harkovskaia [24]

Answer:

(x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

3x' -y' = 13/10

x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

7x' = 35/10 . . . . . . simplify

x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

x = 1/x' = 1/(1/2) = 2

y = 1/y' = 1/(1/5) = 5

(x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.

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3 years ago